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Elden [556K]
2 years ago
14

What is equivalent to the following expression select all that apply.

Mathematics
2 answers:
STALIN [3.7K]2 years ago
8 0
C.6 3 becaue im trying to get point dont lissten to me

jok3333 [9.3K]2 years ago
8 0
<span>the equivalent to the following expression is A and C

</span>
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Put together, Albert and Jason have
Anon25 [30]

Answer:

Step-by-step explanation:

you have to subtract 110 by 42 then when you have that number you divide it by two. then you add 42 to one of the twin numbers. That will be how many jason has, and albert will have the other number you kept the same.

7 0
2 years ago
Please help!!!!!!!!!!!!!!!!
aksik [14]

Step-by-step explanation:

< PQS is exterior angle of the triangle

So,

2X = X + 58

X=58

m < P = 58

m <P QR = 180 - ( 58 + 58 ) =, 64

m < P QS = 116

6 0
2 years ago
Bob's Skate Shop had a profit of $3,563 during the month of August. The company models its profit using P=x^2+10x-12
Vladimir79 [104]
x^2+10x-12 =3563 \\ x^2+10x-12 -3563=0 \\ x^2+10x-3575=0 \\ D=b^2-4ac=10^2-4*1*(-3575)=100+14300=14400 \\ x_{1,2}= \frac{-bб \sqrt{D} }{2a}= \frac{-10б \sqrt{14400} }{2}= \frac{-10б 120 }{2} \\ x_1= -65 \ \ \ \O \\ x_2=55

The company sold 55 skateboards.
4 0
3 years ago
35/100 and 5/100 are proportional right?
maria [59]
In order to know that, you need to divide it from other, if it would be perfect number then your answer will be "YES" & if they not then it will be "NO"

35/100 / 5/100

You can re-write it as:
35/100 * 100/5 = 35/5 = 7

So, they are proportional to each other,.

Hope this helps!

7 0
3 years ago
PLEASE HELP ASAP, ABSURD ANSWERS GET REPORTED GOOD ANSWERS GETT BRAINLIEST +30 POINTSS, PLEASE ANSWER ASAP
makkiz [27]
15. The same polar coordinate as point P will be arrived if: (1) a full rotation of 2nπ is performed or (2) a rotation of (2n+1)π is performed and r is negated. Among the choices, we can see exactly one option with coordinates that follow these two rules, and it is choice A.

ANSWER: A. (1, pi divided by 3 + 2nπ) or (-1, pi divided by 3 + (2n+1)π)

16. To convert the coordinate (3, -3) to polar, we just let x be rcosθ and y be rsinθ. We can get r by solving r^{2}=x^{2}+y^{2} while we can get θ by solving for \theta=arctan(\frac{y}{x}).

r^{2}=(3)^{2}+(-3)^{2}
r=3sqrt(2)

\theta=arctan(\frac{-3}{3})=315degrees

Therefore, one pair of polar coordinates would be (3 square root of 2, 315 degrees) and another one would be (-3 square root of 2, 135 degrees) [note the rule we stated in number 15].

ANSWER: A. (3 square root of 2, 315 degrees), (-3 square root of 2, 135 degrees)

17. Based on your definition that the graph is "circular" with some indentation on the left toward the origin, we can only deduce that the limacon with the form r = a + bcosθ has a value of a that is greater than b. Looking at the choices, our options will be narrowed down to 2 (B and D). Among these, a graph that will look like a circle would be a convex limacon and a limacon of this kind would require that the value of a should be greater than or equal to the value of 2b. Therefore, this will narrow down the answer to option D.

ANSWER: D. r = 4 + cos θ

18. To test for symmetry about the x-axis, we replace the variables r and θ with r and -θ respectively or -r and π-θ. The equation will be symmetric if it will be unchanged (i.e. the same points will still satisfy the new equation).

r=4-4cos\theta
r=4-4cos(-\theta)
-r=4-4cos(\pi-\theta)

If you examine closely, the same set of points will satisfy the equations above. Therefore, the equation is symmetric about the x axis.

For symmetry about the y-axis, we replace r and θ with -r and -θ.

r=4-4cos\theta
-r=4-4cos(-\theta)

Unfortunately, the equation was changed upon substitution therefore we know that it is not symmetric about the y-axis.

For symmetry about the origin, we just replace r and θ with -r and θ respectively.

r=4-4cos\theta
-r=4-4cos\theta

These two equations are not also similar so no symmetry about the origin is exhibited. 

ANSWER: B. x-axis only

19. Let's consider the general form of the ellipse: \frac{x^{2}}{b^{2}}+\frac{y^{2}}{a^{2}}=1.

From the problem we know that a is equal to 58 since we are given the fact that the height of the tunnel is 58ft. To find b, we use the fact that the point (21,29) is a point on the ellipse as stated in the problem.

\frac{x^{2}}{b^{2}}+\frac{y^{2}}{58^{2}}=1
\frac{21^{2}}{b^{2}}+\frac{29^{2}}{58^{2}}=1
\frac{21^{2}}{b^{2}}+0.25=1
441=0.75b^{2}
b^{2}=588

ANSWER: \frac{x^{2}}{588}+\frac{y^{2}}{3364}=1

20. For this item, we follow similar rules stated in item #18. To test for symmetry, we need to examine if the equation will remain unchanged after performing substitutions. 

r=4cos5\theta

x-axis:
r=4cos(-5\theta)
-r=4-4cos[5(\pi-\theta)]

y-axis:
-r=4cos(-5\theta)

origin:
-r=4cos5\theta

If you examine the equations, you'll see that it is only symmetric at the x-axis.

ANSWER: The equation is symmetric about the x-axis.
4 0
3 years ago
Read 2 more answers
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