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Yuri [45]
3 years ago
5

Y = 4x - 6

Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer:

B) 2x - 12x - 18 = 8

Step-by-step explanation:

2x - 3y = 8

If y = 4x - 6, then substitute and solve:

2x - 3(4x - 6) = 8

2x - 12x - 18 = 8

10x - 18 = 8

10x = 8 + 18

10x = 26

x = 26/10

x = 2.6

y = 4(2.6) - 6

y = 10.4 - 6

y = 4.4

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Y = -5/3x + 3 <br> y= 1/3x - 3<br><br> And graphing it
tigry1 [53]

Answer:

Graph.

y=−1/3x+3

y

=

−

1

3

x

−

1

Step-by-step explanation:

8 0
2 years ago
I have this question and I need it done bad... Help please? Picture included I was never taught matrix
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Multiply the numbers on the major axis which are 2 and -9 to get -18.  Subtract from that 3*4 = 12.  So -18-12 = -30.  That's the determinant.
6 0
3 years ago
How would you say the following time?<br> 22.7 seconds
Marianna [84]

Answer: I would say it as “Twenty-Two Point Seven Seconds” Hope this helps you

Step-by-step explanation:

3 0
2 years ago
Saturn's average distance from then sun is about 900 million miles.what is that distance in scientific notation?
IRINA_888 [86]
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3 0
3 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
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