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kupik [55]
3 years ago
15

A parabola opening up or down has vertex (0,- 1) and passes through (6,

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0

Answer:

y + 1 = (11/36)(x - 0)^2

Step-by-step explanation:

Suppose that the parabola opens UP.  We adapt the equation

y - k = a(x - h)^2 as follows:  k = 0 because the vertex is at (0, -1); also h = 1.

Then we have:

y + 1 = a(x - 0)^2

We are told that (6, 10) is on the parabola.  Subtracting 6 for x and 10 for y, we get:

10 + 1 = a(6 - 0)^2, or 11 = a(6^2)  

Then 11/36 = a

The equation of the parabola in vertex form is y + 1 = (11/36)(x - 0)^2

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