Question

A parabola opening up or down has vertex (0,- 1) and passes through (6,

Answer 1

Answer:

y + 1 = (11/36)(x - 0)^2

Step-by-step explanation:

Suppose that the parabola opens UP.  We adapt the equation

y - k = a(x - h)^2 as follows:  k = 0 because the vertex is at (0, -1); also h = 1.

Then we have:

y + 1 = a(x - 0)^2

We are told that (6, 10) is on the parabola.  Subtracting 6 for x and 10 for y, we get:

10 + 1 = a(6 - 0)^2, or 11 = a(6^2)  

Then 11/36 = a

The equation of the parabola in vertex form is y + 1 = (11/36)(x - 0)^2