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Jet001 [13]
3 years ago
9

10x - 5=6x-25 idkk help mee

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

10x - 5=6x-25

Step-by-step explanation:

learn it yourself you stupid

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Factor completely. x2−11x+24
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Step-by-step explanation:

x2-8x-3x+24=0

x(x-8) 3(x+8)

(x-8)(x+8)

x-8=0 or x+8=0

x=8. x= -8

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Write an equation in slope-intercept form for each graph shown.<br><br><br> Please help!!!!!!!
stiv31 [10]

Answer:

y = 2x-3

Step-by-step explanation:

We have 2 points so we can find the slope

m = (y2-y1)/(x2-x1)

   = (1--3)/(2-0)

   = (1+3)/(2-0)

   =4/2

   = 2

The y intercept (where x=0) is -3

We can use the slope intercept form of the equation

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y = 2x-3

3 0
3 years ago
Read 2 more answers
Use cramers Rule to solve the following system:
Jet001 [13]

Answer:

The solution to the system is x=1,y=-2 and z=-5

Step-by-step explanation:

Cramer's rule defines the solution of a system of equations in the following way:

x= \frac{D_x}{D}, y= \frac{D_y}{D} and z= \frac{D_z}{D} where D_x, D_y and D_z are the determinants formed by replacing the x,y and z-column values with the answer-column values respectively. D is the determinant of the system. Let's see how this rule applies to this system.

The system can be written in matrix form like:

\left[\begin{array}{ccc}5&-3&1\\0&2&-3\\7&10&0\end{array}\right]\times \left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}6&11&-13\end{array}\right]

Then each of the previous determinants are given by:

D_x = \left|\begin{array}{ccc}6&-3&1\\11&2&-3\\-13&10&0\end{array}\right|=199 Notice how the x-column has been substituted with the answer-column one.

D_y = \left|\begin{array}{ccc}5&6&1\\0&11&-3\\7&-13&0\end{array}\right|=-398 Notice how the y-column has been substituted with the answer-column one.

D_z = \left|\begin{array}{ccc}5&-3&6\\0&2&11\\7&10&-13\end{array}\right|=-995

Then, substituting the values:

x= \frac{D_x}{D}=\frac{199}{199}\\ x=1

x= \frac{D_y}{D}=\frac{-398}{199}\\ y=-2

x= \frac{D_z}{D}=\frac{-995}{199}\\ x=-5

3 0
3 years ago
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