Answer: True
Solution:
Rearrange the equation to the LHS:
[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0
Factoring x^2+8x+16
x^2 - 4x - 4x - 16
= (x-4) • (x-4)
= = (x+4)2
So now we have an equation
(x + 4)^2 • (x - 4)^2 - (x^2 - 16)^2 = 0
Step 2: Evaluate the following:
(x+4)2 = x^2+8x+16
(x-4)2 = x^2-8x+16
(x^2-16)2 = x^4-32x^2+256
(x^2+8x+16) (x^2-8x+16 ) - (x^4-32x^2+256 )
0 = 0
Hence True
X is the number
when x is decreased by 18, we say 18-x
the result is 14
18-x=14
minus 18 both sides
-x=-32
times both sides by -1
x=32
Ok now that i understand the question better i say it is D
Answer:
6
Step-by-step explanation:
The expression can be rearranged to ...
b = 3 -9/(a+5)
In order for b to be an integer, (a+5) must be an integer divisor of 9. There are exactly 6 of those: ±1, ±3, ±9.
The attached table shows the values (a, b) = (x₁, f(x₁)).
Answer:
w = -3/4 or -0.75
there is only one solution
Step-by-step explanation:
