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Inessa [10]
3 years ago
8

How to use integers in word problems

Mathematics
1 answer:
laila [671]3 years ago
3 0
You can simply use temperature below 0 and above 0 and ask the difference between the first and second temperature.
You might be interested in
») b. The area of the parallelogram is 65 ft2. What is its height? mm th 13 ft 13​
Digiron [165]

Answer:

Five feet

Step-by-step explanation:

H = A ÷ L

H = 65 ÷ 13

H = 5 ft

5 0
3 years ago
The radius of a circle is 12.1 ft. Find the circumference to the nearest tenth}to the nearest tenth
Gnoma [55]

Answer:

76 ft

Step-by-step explanation:

Use the circumference formula, C = 2\pir

Plug in the radius:

C = 2\pir

C = 2\pi(12.1)

C = 76.0

So, the circumference is 76 ft

3 0
3 years ago
Read 2 more answers
XZ=n, WZ=2x-5, and the perimeter of ΔXWZ is 20. What is the value of n?
Sergio039 [100]

Answer:

d.

Step-by-step explanation:

Since it's an isosceles triangle, WX=WZ= 2n-5

Perimeter = n + (2n-5) + (2n-5)

= 5n - 10

The Perimeter is given to be 20

5n - 10 = 20

5n = 30

n = 6

3 0
3 years ago
Find the y-intercept from the line passing through (1, 3) and having slope m=2.
Troyanec [42]

Answer:

The y intercept is 1

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = 2x+b

Substitute the point into the equation and solve for y

3 = 2(1)+b

3 =2+b

1 = b

The y intercept is 1

8 0
3 years ago
Read 2 more answers
Peter is making an "X marks the spot" flag for a treasure hunt. The flag is made of a square white flag with sides of 12 centime
zheka24 [161]

Answer:

34 cm

Step-by-step explanation:

The actual question is How many inches of ribbon Peter will need to make the "X".

Using the Pythagorean theorem, the length of the diagonal of a square with 12 cm sides is:

d^2=12^2+12^2\\d=\sqrt{288}\\ d=16.97\ cm

Since the "X" requires two diagonals, the length of ribbon required is:

L=2*16.97\\L=34\ cm

The length required, rounded to the nearest centimeter, is 34 cm.

6 0
3 years ago
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