Question

I promise i will mark as brainiest

Answer 1

Answer:

A

Step-by-step explanation:

$\frac{2003}{n} = z + \frac{23}{n}$

where z is an integer

$2003 = nz + 23$

$nz = 1980$

$nz = {2}^{2} \times {3}^{2} \times 5 \times 11$

possible values of n

n= {1980, 990, 660, 495, 396, 330, 198, 180, 165, 132, 99, 90, 60, 45, 36, 30, 20, 18, 15, 5, 3}

cardinality of n=21