Question

A rectangle has a length of 2y inches and a width of y - 4 inches. If the perimeter of the rectangle is 22 inches, what is y? What is the length? What is the width?

Answer 1

P = 2( l + w)
Length: 2y
Width: y - 4
P= 22 inches
2(2y) + 2(y - 4) = 22
4y + 2y - 8 = 22
4y + 2y = 6y and add (-8) on both sides of the equation to equal: 6y = 30
Divide 6 from both sides of the equation and you get: y = 5
Check:
4(5) + 2(5) - 8 = 22
20 + 10 - 8 = 22
30 - 8 = 22 ✅