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Tcecarenko [31]
3 years ago
13

(6x^2-2x+4)-(3x^2-4x-3) show work

Mathematics
1 answer:
Rus_ich [418]3 years ago
5 0
Hello The answer is 3x^2 + 2x+7

Now heres how i did it:

1: Simply: 6x^2-2x+4-3x^2+4x+3

2: Combine like term: (6x^2-3x^2)+(-2x+4x)+(4+3)

3: Simply: 3x^2 + 2x +7

Have a great day!

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Please help I’ll mark you as brainliest if correct!
Ket [755]

Answer: 200+50m>1,250

Step-by-step explanation:

It starts with 200 so that is by itself. The m is added to the number that is changing every so often, in this case $50 a month. They need more than $1,250 so we use the greater than sign.

7 0
3 years ago
Read 2 more answers
Two coins are flipped. Draw a sample space diagram showing all possible outcomes
arlik [135]
H = Heads, T = tails
1st Coin       2nd Coin      Final Outcome, ÷ 4 possible outcomes
                    H                     (H,H) 1/4, or 25%
H                  
                    T                     (H,T)  1/4, or 25%

                    H                     (T,H)  1/4, or 25%
T
                    T                     (T,T)   1/4, or 25%

If order does not matter:
T,T: 25%
TH or HT: 50%
HH: 25%
7 0
3 years ago
A company with n employees publishes an internal calendar, where each day lists the employees having a birthday that day. What i
lutik1710 [3]

Answer: 1-(\frac{364}{365})^n

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^x, where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.

We assume that the total number of days in a particular year are 365.

Then , the probability for each employee to have birthday on a certain day :

p=\dfrac{1}{365}

Given : The number of employee in the company = n

Then, the probability there is at least one day in a year when nobody has a birthday is given by :-

P(x\geq1)=1-P(x

Hence, the probability there is at least one day in a year when nobody has a birthday =1-(\frac{364}{365})^n

5 0
3 years ago
Dennis decided he wanted to go to the carnival. The carnival charges $6.00 for entry and $1.50 for each ride.
myrzilka [38]

We want to create a linear equation to model the given situation.

A) c(r) = $6.00 + $1.50*r

B) 19 rides.

We know that the carnival charges $6.00 for entry plus $1.50 for each ride.

A) With the given information we can see that if you ride for r rides, then the cost equation will be:

c(r) = $6.00 + $1.50*r

Where c(r) is the cost for going to the carnival and doing r rides.

B) If you have $35.00, then we can solve:

c(r) = $35.00 =  $6.00 + $1.50*r

Now we can solve the equation for r.

$35.00 =  $6.00 + $1.50*r

$35.00 -  $6.00 = $1.50*r

$29.00 = $1.50*r

$29.00/$1.50 = r = 19.33

Rounding to the next whole number we get: r = 19

This means that with $35.00, Dennis could go to 19 rides.

If you want to learn more, you can read:

brainly.com/question/13738061

7 0
3 years ago
What is the solution to the following inequality? 3n + 6 > 15
frosja888 [35]

Answer:

n > 3

Step-by-step explanation:

Given

3n + 6 > 15 ( subtract 6 from both sides )

3n > 9 ( divide both sides by 3 )

n > 3

6 0
3 years ago
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