Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
Answer:
2
Step-by-step explanation:
rise over run = y/x
3/1.5= 2
Answer: (x−2)(x−2)
The middle number is -4 and the last number is 4.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get -4
Multiply together to get 4
Can you think of the two numbers?
Try -2 and -2:
-2+-2 = -4
-2*-2 = 4
Fill in the blanks in
(x+_)(x+_)
with -2 and -2 to get...
(x-2)(x-2)
Answer:
(x−2)(x−2)
so the answer is D.
Answer:
The value of k with given points and slop = 11
Step-by-step explanation:
Given that a line passes through two points having slop (m) = 2
co ordinates of points are (1 , 3) and (5 , k)
Now slop of line can be written as,
Slop = 
Or, m =
2 = 
Or, 2 = 
So , k - 3 = 8
∴ K = 8+3 = 11
Hence the value of k with given points and slop = 11 Answer
Well, since you didn't attach the options. I will try to simplify the problem for you.⬇
Problem➡8/9 ÷2/3
~How to solve it ⬇
8(3) / 9(2) = 24/18
So, that means that your answer might have to be
1 1/3~
