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DIA [1.3K]
4 years ago
5

Which of the following indicates the main benefit of having a larger hard drive on a computer

Computers and Technology
1 answer:
dem82 [27]4 years ago
8 0
I would say the primary Beni fit is more space for storage , but also it does effect the speed eventually. If your hard drive is almost full, everything will be slower
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Given that note, write a program which tells us the major scale starting at that note, using the pattern above. In the main bloc
White raven [17]

<u>Solution and Explanation:</u>

the_notes = ['C','C#','D','D#','E','F','F#','G','G#','A','A#','B'] #original list

def get_scale(choice): #function to get the major diatonic scale

steps=[1,1,.5,1,1,1,.5] #separate list for steps

size=None

for i in range(0,12): #loop to find out the index of the note entered

if(the_notes[i]==choice):

size =i

break

new_notes=the_notes[size:] + the_notes[:size]

#the above statement rotate the list so that the entered note can become the first note in the new list(i.e new notes)

index =0 #

scale="" #a string to store the major diatonic scale

for i in range(0,7):

scale+=new_notes[index]+" "

if(steps[i]==1):

index = index+2

else:

index=index+1

return scale

#main block

while(1):

choice=input("What scale do you want or Q to quit? ")

if(choice=='Q'):

break

elif(choice in the_notes):

print(get_scale(choice))

else:

print("That is not a note")

5 0
3 years ago
The following code segment is a count-controlled loop going from 1 to 5. At each iteration, the loop counter is either printed o
quester [9]

Answer:

True.

Explanation:

For all the count values, if Ranfun() returns true then all the values of count would be printed. Then the sequence of count values printed would be 1 2 3 4 5. Also for all the values of count if Ranfun() returns false then all the values would be enqueued. When we try to dequeue elements from queue we would get them in the same order of their entry into the queue. Thus, the sequence would be 1 2 3 4 5. Hence, we can say that this output sequence is possible. TRUE.

4 0
3 years ago
A person can receive an electric shock by
trapecia [35]

the answer is C. completing an electrical circuit

4 0
4 years ago
Read 2 more answers
create a new Java application called "CheckString" (without the quotation marks) according to the following guidelines.** Each m
jok3333 [9.3K]

Answer:

The Java code is given below

Explanation:

import java.io.*;

import java.util.Scanner;

import java.util.ArrayList;

public class StringCheck{

//There are several implementation approaches. This is one example framework/outline which might be helpful. Please feel free to try other approaches.

public static void checkWord(String word) throws Exception {

// Uses charAt method to test if the first letter of string variable word

// is a character. If not, throw new exception

if(Character.isLetter(word.charAt(0))){

 return;

}else{

 throw new Exception("This is not a word");

}

}

public static String getWord() {

// Declare a local scanner

// Prompt the user to enter a word

// Think about using a loop to give the user multiple opportunities to correctly enter a string

// Read into a string

// Call checkWord method passing the string as a parameter

// checkWord can throw an exception; call checkWord in a try/catch block

// Return the string to main if a valid string

Scanner sc = new Scanner(System.in);

boolean st = true;

String word = null;

while(st){

 System.out.println("Enter a Word : ");

 word = sc.next();

 try{

  checkWord(word);

  st = false;

 }catch(Exception e){

  System.out.println(e);

  st = true;

 }

}

sc.close();

return word;

}

public static void writeFile(String[] arrayToWrite, String filename) throws IOException {

// Example using FileWriter but PrintWriter could be used instead

// Create a FileWriter object

FileWriter fileWordStream = new FileWriter(filename);

// Use a loop to write string elements in arrayToWrite to fileWordStream

for(int i = 0;i<arrayToWrite.length;i++){

fileWordStream.write(arrayToWrite[i]+System.lineSeparator());

}

fileWordStream.flush();

fileWordStream.close();

// In the loop use the lineSeparator method to put each string on its own line

}

public static ArrayList readFile(String filename) throws FileNotFoundException, IOException {

// Declare local ArrayList

ArrayList<String> words = new ArrayList<>();

// Create a new File object using filename parameter

File file = new File(filename);

// Check if the file exists, if not throw a new exception

if(!file.exists()){

 throw new FileNotFoundException("File not Found");

}

// Create a new BufferedReader object      

Scanner fsc = new Scanner(file);

// use a loop and the readLine method to read each string (on its own line) from the file

while(fsc.hasNextLine()){

words.add(fsc.nextLine());

}

fsc.close();

// return the filled ArrayList to main

return words;

}

public static void main(String[] args) {

// create a string with literal values to write to the file

String[] testData = {"cat", "dog", "rabbit"};

// Create an ArrayList for reading the file

ArrayList<String> words = new ArrayList<>();

// Declare a string variable containing the file name "data.txt"

String file = "data.txt";

// Call getWord, assign the returned string to a variable and display it

String word = getWord();

System.out.println("The word is : "+word);

// Call writeFile and readFile methods in a try block

try{

writeFile(testData,file);

words = readFile(file);

// Printout the contents of the ArrayList after the call to readFile

for(int i = 0;i<words.size();i++){

 System.out.println(words.get(i));

}

}catch(FileNotFoundException e){

System.out.println(e);

}catch(IOException e){

System.out.println("IOException: error occured in input output");

}

// catch two types of exceptions

}

}

4 0
3 years ago
Before you can use the Management Studio to work with the objects in a database, you must ___________ the database files (i.e.,
Lelu [443]

Answer:

You must attach the database files

Explanation:

4 0
3 years ago
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