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Afina-wow [57]
2 years ago
13

I NEED HELP NOW ur really gonna need to solve this 10t-5=60

Mathematics
2 answers:
asambeis [7]2 years ago
8 0

Answer:

t = 6.5

Step-by-step explanation:

10t - 5 = 60

Add 5 to each side

10t -5+5 = 60+5

10 t = 65

Divide each side by 10

10t/10 = 65/10

t = 6.5

faltersainse [42]2 years ago
3 0

Answer:

\huge \: t =  \frac{13}{2}

Step-by-step explanation:

10t - 5 = 60

Using the addition property add 5 to both sides of the equation

That's

10t - 5 + 5 = 60 + 5 \\ 10t = 65

<u>Divide both sides by 10</u>

\frac{10t}{10}  =  \frac{65}{10}  \\  t =  \frac{65}{10}

<u>Reduce the fraction with 5</u>

We have the final answer as

t =  \frac{13}{2}  \\

Hope this helps you

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kozerog [31]

INFORMATION:

We know that:

- stack of mail consists of 8 bills, 10 letters, and 6 advertisements.

- One piece of mail is drawn at random and put aside. Then a second piece of mail is drawn.

And we must find P (both are letters)

STEP BY STEP EXPLANATION:

To find the probability, we need to know that we have two events. First, when one piece of mail is drawn at random and put aside and, second, when a second piece of mail is drawn.

These two events are dependent. If A and B are dependent events, P(A and B) = P(A) • P(B after A) where P(B after A) is the probability that B occurs after A has occurred.

So, first

- Probability of A (the first piece is letter)

P(A)=\frac{favorable\text{ }cases}{total\text{ cases}}=\frac{10}{24}

- Probability of B after A

Since A already occurred and one piece of the mail was drawn (a letter), now in total we would have 9 letter and 23 total pieces

P(B\text{ after }A)=\frac{9}{23}

Finally, replacing in the initial formula

P(A\text{ and }B)=\frac{10}{24}\cdot\frac{9}{23}=\frac{90}{552}=0.1630

Finally, the probability would be 0.1630

ANSWER:

P (both are letters) = 0.1630

8 0
1 year ago
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\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's simplify ~

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