All categories

3 years ago

I NEED HELP NOW ur really gonna need to solve this 10t-5=60

Mathematics

2 answers:

asambeis [7]3 years ago

8 0

Answer:

t = 6.5

Step-by-step explanation:

10t - 5 = 60

Add 5 to each side

10t -5+5 = 60+5

10 t = 65

Divide each side by 10

10t/10 = 65/10

t = 6.5

faltersainse [42]3 years ago

3 0

Answer:

$\huge \: t = \frac{13}{2}$

Step-by-step explanation:

$10t - 5 = 60$

Using the addition property add 5 to both sides of the equation

That's

$10t - 5 + 5 = 60 + 5 \\ 10t = 65$

<u>Divide both sides by 10</u>

$\frac{10t}{10} = \frac{65}{10} \\ t = \frac{65}{10}$

<u>Reduce the fraction with 5</u>

We have the final answer as

$t = \frac{13}{2} \\$

Hope this helps you

You might be interested in

15 < −5x can someone please solve for x?

Varvara68 [4.7K]

Answer:

x <-3

Step-by-step explanation:

15 <-5x

divide both sides by 5 but since the coefficient of x is negative after dividing the sign changes.

x <-3

4 0

3 years ago

Read 2 more answers

Please answer soon (45 Points)

NISA [10]

Answer:

$10 each week

Step-by-step explanation:

The boxes sum is equal to 40.

(x-2)+(x-2)+(x-2)+(x-2)+(x-2) = 40

5x-10 = 40

5x=50

x =50/5

x=10

6 0

2 years ago

Read 2 more answers

Which expressions are equivalent to

klio [65]

Answer:

Tired

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Please help me asap

Marat540 [252]

Answer:

yes

Step-by-step explanation:

it's right i think i hel8

4 0

3 years ago

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0

3 years ago