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andrezito [222]
3 years ago
15

What is the integral of sqrt(1-cosx)?

Mathematics
1 answer:
bekas [8.4K]3 years ago
7 0

we can apply the rules of trigonometry to determine the integral of the function: The exponent is added by 1 and the function is multiplied by the reciprocal of the added power. Hence, 
y' = sqrt (1-cosx)y  = (2/3) (1 - cos x )^ (3/2) *(x - sin x) y  = (2/3) *(x - sin x) (1 - cos x )^ (3/2)
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Graph the solution set: x-2y&gt;4 <br> (with explaining please)
KatRina [158]

the Answer is x>2y+4

x−2y>4

Step 1: Add 2y to both sides.

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7 0
3 years ago
What is an equation of the line that passes through the point (1, -2) and is parallel
Oliga [24]

Answer:

y = -6x + 4

Step-by-step explanation:

2 parallel lines should have equal slope

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6 0
3 years ago
Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogram, to solve this proble
EleoNora [17]
H=27

25*27=675

Hopes this helps.
3 0
3 years ago
Read 2 more answers
Can someone please answer it correctly if it’s correct I will mark you brainliest
oksian1 [2.3K]

Answer: 945

Step-by-step explanation:

220% x 450

45 + 400 + 400

945

<h3><u><em>Hope this helps!!!</em></u></h3>

4 0
3 years ago
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