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PSYCHO15rus [73]
3 years ago
14

What property is k•1=k

Mathematics
1 answer:
viktelen [127]3 years ago
8 0
That is the multiplication identity.
You might be interested in
Evaluate 6x + 11 when x = 7
nlexa [21]

Answer:

53

Step-by-step explanation:

To evaluate 6x + 11, we must substitute the value of x.

Since we know that x = 7, it is easier to evaluate the expression;

6x + 11

6(7) + 11

Since 6 is outside the parenthesis, we must multiply everything inside the parenthesis by 6;

6(7) + 11

42 + 11

When you add the two numbers you get:

53

4 0
4 years ago
Plz help 14 points
ValentinkaMS [17]
 1)Rewrite the table:
70,  49,  34.3,  24.01,  11.807 {The original size of the wound =70}

2) write the quotient of each number by the number before & notice the value:

49/70= 0.7
34.3/49 = 0.7
24.01/34.3 =0.7
16.0807/24.01 = 0.67 ≈0.7
You notice this is a geometric progression with r 0.7
The last term in a GP =ar^⁽ⁿ⁻¹⁾


3) Domain and Range of this function:
Last term = a₁.rⁿ⁻¹. let last term be y==> f(n) = y =70(0.7)ⁿ⁻¹
or f(n) = y = 70(0.7)ⁿ / 0.7==> f(n) = [(0.7)ⁿ ]/ 100.
This is a decreasing exponential function where the coefficient
raised to n is < 1.
The domain is for all n>= 0.
When n→∞, f(n)→0; For n=0==>f(n) =70. So the range of f(n) is:<=70

7 0
4 years ago
The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f
Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

h(t)=-16t^{2}+25t+5

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

so

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

h(t)=-16(t^{2}-\frac{25}{16}t)+5

Complete the square

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}

Rewrite as perfect squares

h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

The vertex is the point (\frac{25}{32},\frac{945}{64})

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

16(t-\frac{25}{32})^{2}=\frac{945}{64}

(t-\frac{25}{32})^{2}=\frac{945}{1,024}

square root both sides

(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}

t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}

the positive value is

t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec

8 0
3 years ago
4^1/2 ft to inches
motikmotik

Answer:

54 :)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the largest number of consecutive integers whose sum is 2003?
Sladkaya [172]
2003 \div 2=1001.5

Go .5 below and .5 above this answer to get your consecutive integers.

Therefore the answer is 1001 and 1002.
4 0
3 years ago
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