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tamaranim1 [39]
2 years ago
14

A car is driving at a speed of 65 miles per hour. What is the speed of the car in feet per minute?

Mathematics
1 answer:
tino4ka555 [31]2 years ago
5 0

Answer:

The car is driving at a speed of 5,720 feet per minute.

Step-by-step explanation:

1 mile = 5,280 feet

65 miles = 343,200 feet

1 hour = 60 minutes

343,200ft ÷ 60min = 5,720 feet per minute

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Salsk061 [2.6K]

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1 year ago
The hourly median power (in decibels) of received radio signals transmitted between two cities
trasher [3.6K]

Using the lognormal and the binomial distributions, it is found that:

  • The 90th percentile of this distribution is of 136 dB.
  • There is a 0.9147 = 91.47% probability that received power for one of these radio signals is  less than 150 decibels.
  • There is a 0.0065 = 0.65% probability that for  6 of these signals, the received power is less than 150 decibels.

In a <em>lognormal </em>distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{\ln{X} - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 3.5.
  • The standard deviation is of \sigma = \sqrt{1.22}

Question 1:

The 90th percentile is X when Z has a p-value of 0.9, hence <u>X when Z = 1.28.</u>

Z = \frac{\ln{X} - \mu}{\sigma}

1.28 = \frac{\ln{X} - 3.5}{\sqrt{1.22}}

\ln{X} - 3.5 = 1.28\sqrt{1.22}

\ln{X} = 1.28\sqrt{1.22} + 3.5

e^{\ln{X}} = e^{1.28\sqrt{1.22} + 3.5}

X = 136

The 90th percentile of this distribution is of 136 dB.

Question 2:

The probability is the <u>p-value of Z when X = 150</u>, hence:

Z = \frac{\ln{X} - \mu}{\sigma}

Z = \frac{\ln{150} - 3.5}{\sqrt{1.22}}

Z = 1.37

Z = 1.37 has a p-value of 0.9147.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is  less than 150 decibels.

Question 3:

10 signals, hence, the binomial distribution is used.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, we have that p = 0.9147, n = 10, and we want to find P(X = 6), then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{10,6}.(0.9147)^{6}.(0.0853)^{4} = 0.0065

There is a 0.0065 = 0.65% probability that for  6 of these signals, the received power is less than 150 decibels.

You can learn more about the binomial distribution at brainly.com/question/24863377

5 0
2 years ago
Which of the following points is between 2 and -3 on the number line?<br> -4 3 -2 -5
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Answer:

-2

Step-by-step explanation:

-5  -4  -3  <u>-2</u>  -1  0  1  2 3  4  5

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3 years ago
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Teehee buddy boy yeetmcskeet man
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3 years ago
What is the resulting equation when the expression for y in the second equation is substituted into the first equation-3x+2y=-3
Alex

Answer:

x=-5/11, y=-9/11. (-5/11, -9/11).

Step-by-step explanation:

3x+2y=-3

y=4x+1

---------------

3x+2(4x+1)=-3

3x+8x+2=-3

11x=-3-2

11x=-5

x=-5/11

y=4(-5/11)+1

y=-20/11+11/11

y=-9/11

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2 years ago
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