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tatiyna
3 years ago
8

Write the domain as an inequality​

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
4 0

Answer:

x\leq 0

Step-by-step explanation:

The domain is the span of x-values covered by the graph.

From the graph, we can see that the x-values covered by the graph is all values to the left of zero including zero.

Therefore, the domain is all x-values less than or equal to 0:

x\leq 0

Further notes:

In interval notation, this is:

(-\infty,0]

Minchanka [31]3 years ago
3 0

Answer:

\huge \boxed{x\geq 0}

Step-by-step explanation:

The domain is all possible values for x or where the x values covers the graph.

All the values for x are less or equal to 0 as shown in the graph.

This can be written as an inequality:

x\geq 0

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All the edges of a cube are expanding at a rate of 4 in. per second. How fast is the volume changing when each edge is 10 in. lo
Greeley [361]

Given:

All the edges of a cube are expanding at a rate of 4 in. per second.

To find:

The rate of change in volume when each edge is 10 in. long.

Solution:

Let a be the edge of the cube.

According to the question, we get

\dfrac{da}{dt}=4\text{ in./sec}

a=10\text{ in.}

We know that, volume of a cube is

V=a^3

Differentiate with respect to t.

\dfrac{dV}{dt}=\dfrac{d}{dt}a^3

\dfrac{dV}{dt}=(3a^2)\times \dfrac{da}{dt}

Putting the given values, we get

\dfrac{dV}{dt}=(3(10)^2)\times 4

\dfrac{dV}{dt}=3(100)\times 4

\dfrac{dV}{dt}=300\times 4

\dfrac{dV}{dt}=1200\text{ in}^3\text{/sec}

Therefore, the rate of change in volume 1200 cubic inches per second.

5 0
3 years ago
If (x + 4) is a factor of f(x), which of the following must be true?
GalinKa [24]
F(-4) = 0

Here, we replace x with -4. In doing so, we see that (-4+4) is indeed 0, making this the correct answer.

The next two choices are incorrect since only -4 is a root of f(x), as explained above (a root occurs when the function equals zero when plugging in that “root”).

The last answer is incorrect since plugging in 4 will get f(4)=8.
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What two numbers can be multiplied to be -150 and added to be 5
pav-90 [236]
Xy = -150
x + y = 5

     x + y = 5
x - x + y = -x + 5
           y = -x + 5

                                                       xy = -150
                                             x(-x + 5) = -150
                                         x(-x) + x(5) = -150
                                               -x² + 5x = -150
                                     -x² + 5x + 150 = 0
                       -1(x²) - 1(-5x) - 1(-150) = 0
                                  -1(x² - 5x - 150) = 0
                                               -1            -1
                                        x² - 5x - 150 = 0
                                        x = -(-5) ± √((-5)² - 4(1)(-150))
                                                                2(1)
                                        x = 5 ± √(25 + 600)
                                                         2
                                        x = 5 ± √(625)
                                                     2
                                        x = 5 ± 25
                                                 2
                                        x = 2.5 ± 12.5
                                        x = 2.5 + 12.5    or    x = 2.5 - 12.5
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    x + y = 5
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    (x, y) = (15, -10)

            or

    x + y = 5
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+ 10    + 10
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