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3 years ago

To increase an amount by 85% what single multiplier would i need to use?

1 answer:

7 0

The initial amount is 100%. you want to decrease it by 85%:

The decreased amount will be 100% - 85 % = 15%
If te amount was "x" and you wand to decreased by 85%, then
you multiply x.15% = 15%.x

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The drama club at Math Academy High School sold tickets to their end of the year play. On Monday they sold 80 tickets for a tota

riadik2000 [5.3K]

Answer: OPTION A

Step-by-step explanation:

Let be "a" the number of adults tickets they sold and "s" the number student of tickets they sold.

With the information given in the exercise you can set up the following System of equations:

$\left \{ {{a+s=80} \atop {6a+4.5s=426}} \right.$

Use the Elimination method to solve the system of equations:

1. Multiply the first equation by -6.

2. Add the equations.

3. Solve for "s" in order to find its value.

Then:

$\left \{ {{-6a+-6s=-480} \atop {6a+4.5s=426}} \right.\\............................\\-1.5s=-54\\\\s=36$

4. Finally, substitute the value of "s" into the first equation and solve for "a":

$a+36=80\\\\a=80-36\\\\a=44$

3 0

4 years ago

Two jets leave an airbase at the same time and travel in opposite directions, One jet travels 71mi/h faster than the other. If t

KATRIN_1 [288]

jet1 = 549 mi/h

jet2 = 620 mi/h

x= jet1

x + 71 = jet2

6 hours

6 * x

6 * x + 71

6x + 6x + 426 = 7014

12x = 7014 - 426

12x = 6588

x = 6588/12

x= 549

x + 71 = 620

wyzant

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3 years ago

Pls send me questions on functions only

PilotLPTM [1.2K]

Wym ? Like me send u functions ?

6 0

3 years ago

Please answer !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!

zvonat [6]

i would probably use an iv or a blood simple

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3 years ago

In a prior sample of U.S. adults, the Center for Disease Control (CDC), found that 8% of the people in this sample had pinworm b

kow [346]

Answer: a) 453 b) 1537

Step-by-step explanation:

As per given , we have

Margin of error : E= 0.025

Critical value for 95% confidence interval : $z_{\alpha/2}=1.96$

a) The prior estimate of population proportion : p=0.08

Required sample size :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.08(1-0.08)(\dfrac{1.96}{0.025})^2\\\\=452.386816\approx453$

The minimum sample size is 453 U.S. adults.

b) Since the prior estimate of population proportion is not available , so we take p= 0.5

Required sample size :-

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.025})^2\\\\=1536.64\approx1537$

The minimum sample size is 1537 U.S. adults.

5 0

4 years ago