Two jets leave an airbase at the same time and travel in opposite directions, One jet travels 71mi/h faster than the other. If t
wo jets are 7014 miles apart after 6 hours what is the speed of each jet?
1 answer:
jet1 = 549 mi/h
jet2 = 620 mi/h
x= jet1
x + 71 = jet2
6 hours
6 * x
6 * x + 71
6x + 6x + 426 = 7014
12x = 7014 - 426
12x = 6588
x = 6588/12
x= 549
x + 71 = 620
wyzant
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