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2 years ago

Subtract -2x^2 + 3x - 9 from 8x^2 +10x - 10

Mathematics

1 answer:

Rina8888 [55]2 years ago

8 0

Answer:

8x^2+10x-10-(-2x^2+3x-9)=10x2+7x-1

Step-by-step explanation:

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Help me i nedd help...........

VMariaS [17]

Answer:

The answer is 10 12/85 Hope you pass!

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2 years ago

What is the answer for Expanding 2t(6t-3)

Jlenok [28]

Answer:

Step-by-step explanation:

12t2 - 6t

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2 years ago

The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0.30, and the sample statistics

IrinaK [193]

Answer: 0.84

Step-by-step explanation:

let p be the population proportion of adults who smoked a cigarette in the past week.

As per given , we have

$H_a: p$

Sample size : n= 1491

The sample proportion of adults smoked a cigarette= $\hat{p}=\dfrac{x}{n}=\dfrac{462}{1491}=0.30985915493\approx0.31$

The test statistic for proportion is given by :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Substitute all the values , we get

$z=\dfrac{0.31-0.30}{\sqrt{\dfrac{0.30(1-0.30)}{1491}}}\\\\=\dfrac{0.01}{\sqrt{0.000141}}\\\\=\dfrac{0.01}{0.011874342087}=0.84261497731\approx0.84$

Hence, the value of the test statistic = 0.84

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2 years ago

Help Please. . . . .

Anika [276]

Answer:

angle 5 = angle 1

angle 6=angle 3

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2 years ago

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago