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3 years ago

Please help me on problems 17,18,19,20...explanation needed Thanks:)

Mathematics

1 answer:

nordsb [41]3 years ago

5 0

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Solve the equation-4(x+10)-6=-3(x-2)<br>

marta [7]

Answer:

x = -52

Step-by-step explanation:

-4x-46+46=-3x+6+46

-4x=-3x+52

-4x+3x=-3x+52+3x

8 0

3 years ago

Read 2 more answers

Whats the elasped time between 9:00 and 1:30

Tasya [4]

Answer:

4 hours and 30 minutes

Step-by-step explanation:

I'll assume you have a basic knowledge of time and know the sequence. So all you do is count to 1:00 and see how many steps you took. In this case 4, but then you have 30 minutes left. Add that to the 4 hours, and you have a total of 4 hours and 30 minutes of elapsed time.

Hope this helps :)

7 0

2 years ago

Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

3 years ago

Consider this algebraic expression: –3x + x + 5 Use the algebra tiles to model the expression.

luda_lava [24]

For this case, we have the following expression:

$-3x + x + 5$

We simplify the expression:

If we add similar terms, taking into account that different signs are subtracted and the sign of the greater one is placed, we have that $-3x + x = -2x$