Given two numbers x and y such that:
x + y = 12 ... (1)
<span>two numbers will maximize the product g</span>
from equation (1)
y = 12 - x
Using this value of y, we represent xy as
xy = f(x)= x(12 - x)
f(x) = 12x - x^2
Differentiating the above function:
f'(x) = 12 - 2x
Maximum value of f(x) occurs at point for which f'(x) = 0.
Equating f'(x) to 0 we get:
12 - 2x = 0
2x = 12
> x = 12/2 = 6
Substituting this value of x in equation (2):
y = 12 - 6 = 6
Therefore, value of xy is maximum when:
x = 6 and y = 6
The maximum value of xy = 6*6 = 36
Answer: 100+1.28(1/2)=100.64
Step-by-step explanation:
A random sample of size 16 is to be taken from a normal population having mean 100 and variance 4. ... The 90th percentile of the normal curve, according to the table I was provided, was equal to 1.28 standard units above the mean.
Step-by-step explanation:
1) x+6 =4
x. =4-6
x. =-2
2) x-(-4) =-6
x+ 4. =-6
x. =-6-4
x. =-10
3)2(x-1)=-200
2x-2 =-200
2x. = -200+2
2x. = -198
x. = -198/2
x. = -99
4)2x+(-3) =-23
2x-3. =-23
2x. =-23+3
2x. =-20
x. =-20/2
x. = -10
It should be 2 but i’m not positive
11154/52= 214 1/2 is the answer to this question
