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Blababa [14]
3 years ago
13

Solve Highschool Pre cal

Mathematics
1 answer:
Bezzdna [24]3 years ago
6 0

Option C:

\ln 64 y^{2}

Solution:

Given expression: 2 ln 8 + 2 ln y

Applying log rule a \log b=\log b^{a}  in the above expression.  

⇒ 2 \ln 8+2 \ln y=\ln 8^{2}+\ln y^{2}

Applying log rule \log a+\log b=\log (a b) in the above expression.

⇒ \ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)

We know that 8^{2}=64

⇒ \ln \left(8^{2} y^{2}\right)=\ln 64 y^{2}

Hence, the expression in single natural logarithm is \ln 64 y^{2}.

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Step-by-step explanation:

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2 years ago
A sneaker company can make 50 pairs of sneakers for every 6 yards of material. Make a table to show the relation between materia
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A sneaker company can make 50 pairs of sneakers for every 6 yards of material.

Then in each case you can consider proportion.

1. 50 pairs -- 6 yards,

80 pairs -- x yards.

Mathematically,

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Mathematically,

\dfrac{50}{100}=\dfrac{6}{x},\\ \\x=\dfrac{100\cdot 6}{50}=12\ yards.

3. 50 pairs -- 6 yards,

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Mathematically,

\dfrac{50}{120}=\dfrac{6}{x},\\ \\x=\dfrac{120\cdot 6}{50}=14.4\ yards.

4. 50 pairs -- 6 yards,

140 pairs -- x yards.

Mathematically,

\dfrac{50}{140}=\dfrac{6}{x},\\ \\x=\dfrac{140\cdot 6}{50}=16.8\ yards.

Thus, the table is

\begin{array}{cc}\text{Pairs}&\text{Yards}\\50&6\\80&9.6\\100&12\\120&14.4\\140&16.8\end{array}

The domain of the relation is the set \{50,80,100,120,140\} and the range of the relation is \{6,9.6,12,14.4,16.8\}.See attached diagram for the graph of the relation.

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3 years ago
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$39.90 total paid divided by 10 watermelons is $3.99

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Three pieces are left. Hope this helps!

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Snezhnost [94]

Answer:

1) x=3, y=-3

Step-by-step explanation:

10x + 7y = 9 —— (1)

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(1) + (2)

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