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Blababa [14]
3 years ago
13

Solve Highschool Pre cal

Mathematics
1 answer:
Bezzdna [24]3 years ago
6 0

Option C:

\ln 64 y^{2}

Solution:

Given expression: 2 ln 8 + 2 ln y

Applying log rule a \log b=\log b^{a}  in the above expression.  

⇒ 2 \ln 8+2 \ln y=\ln 8^{2}+\ln y^{2}

Applying log rule \log a+\log b=\log (a b) in the above expression.

⇒ \ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)

We know that 8^{2}=64

⇒ \ln \left(8^{2} y^{2}\right)=\ln 64 y^{2}

Hence, the expression in single natural logarithm is \ln 64 y^{2}.

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Using synthetic division, find the quotient Q(x) and the remainder R if the polynomial P(x) = x3 − 2x2 − 5x + 6 is divided by (x
VLD [36.1K]

Answer:

Step-by-step explanation:

1_|   1     -2     -5    6

     <u>          1      -1   -6</u>

       1     -1      -6   0

Q(x)= x^2 - x - 6

R: 0

4 0
3 years ago
At a harvest 16 ears are being picked foot every 18 peppers. If 19 peppers have been picked, how many eats of corn have been pic
ExtremeBDS [4]

The number of eats of corn which have been picked is; 16.9 corns.

<h3>How many eats of corn have been picked?</h3>

According to the question; 16 eats of corn are being picked foot every 18 peppers. In essence, the ratio of corns to peppers is; 16/18.

Hence, it follows that the number of corns which corresponds to 19 peppers been picked can be evaluated as follows;

16/18 = x/19

x = (19×16)/18

x = 16.9 eats of corn.

Read more on ratios;

brainly.com/question/13513438

#SPJ1

7 0
2 years ago
a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
4 years ago
Need help asap!! No links please!!! I will give brainliest to best answer. Don't answer if you don't know!
Olin [163]

Answer:

3/4 students (75/100)

Step-by-step explanation:

in total there are 100 students. 75 of them either like sports or works.

6 0
2 years ago
Suppose f(x) = x^2. What is the graph of g(x) =f(4x)?
Alika [10]

Answer:

your y-intercept is 0 and slope is 4 so any line with zero slope it will be horizontal

6 0
3 years ago
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