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3 years ago

What is equivalent to -6 to the -5 power?

Mathematics

1 answer:

Anarel [89]3 years ago

8 0

Answer:

$-\frac{1}{7776}$

Step-by-step explanation:

Put negative exponents in the denominator to make them positive.

$\frac{1}{-6^5}$

$\frac{1}{-6*-6*-6*-6*-6}$

$\frac{1}{-7776}$

$-\frac{1}{7776}$

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100 points. Easy question. Topic: Fractions. ONLY COMPLETE QUESTION 1

Basile [38]

Answer: 1/4 full.

Step-by-step explanation:

The question is asking for how much gas will be left in the tank after 2/3 of the gas in the tank is used.

There is currently 3/4 of the tank remaining.

To find 2/3 of 3/4, you can multiply the fractions together.

Do this by multiplying both numerators and both denominators:

$\frac{2}{3} *\frac{3}{4} = \frac{2*3}{3*4} = \frac{6}{12}$

Then, subtract 6/12 from 3/4. You can do this by simplifying the first fraction to 2/4 (divide both the numerator and denominator by 3).

3/4 - 2/4 = 1/4

There will be 1/4 of the tank left.

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3 years ago

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kramer

Answer:

Solution given

tan θ=opposite/adjacent=y/x is a required answer.

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3 years ago

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according to the Greek mathematician Zeno, if each bounce of a bakl is half the height of the bounce begire it, the ball will ne

USPshnik [31]

You have to say what or where point B and C is for me to answer it

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3 years ago

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What is the absolute value equation that has the solution x= -10 and x= -5

Anna11 [10]

the answer is
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3 years ago

Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

Translation:

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

8 0

3 years ago