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arlik [135]
3 years ago
5

Quadratic Functions. SOS

Mathematics
1 answer:
natulia [17]3 years ago
6 0

1. replace x with zero and solve: y = 4

2. vertex = (3,0)

3. f(x) = -(x-2)(x+5)

4. x=-1/4

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Answer:

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Step-by-step explanation:

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3 years ago
Will mark as brainliest<br><br> ...
Anuta_ua [19.1K]

Answer:

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Olin [163]

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Step-by-step explanation:

\displaystyle\\\left \{ {{6x+4y=10\ \ \ \ \ (1)} \atop {12x+y=-29\ \ \ \ (2)}} \right.\\  We\  multiply\  both\  sides\  of\  equation\  (1)\  by\  -2:\\\left \{ {{(-2)*6x+(-2)*4y=(-2)*10} \atop {12x+y=-29}} \right. \\\\\left \{ {{-12x-8y=-20} \atop {12x+y=-29}} \right. \\We\  summarize\  equations\  (1)\  and\  (2):\\-7y=-49\\-7*y=-7*7\\Divide\  both\  sides\  of\  the\  equation\  by\  -7:\\y=7.\\We\  substitute\  the\  value\  of\  y\  into \ equation\  (1):\\6x+4*7=10\\6x+28=10\\6x+28-28=10-28\\6x=-18\\6*x=6*(-3)\\Divide\  both\  sides\  of\  the\  equation\  by\  6:\\x=-3.

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1 year ago
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