Answer:
x=-6 is an extraneous solution
Step-by-step explanation:
we have
squared both sides
solve the quadratic equation by graphing
The solution is x=-6 and x=-1
see the attached figure
<u><em>Verify each solution</em></u>
substitute the value of x in the original expression
For x=-6
----> is not true
so
Is an extraneous solution
For x=-1
----> is true
so
Is the solution
I don’t understand your question, can you give more details please
To find the solution, we use the substitution method.
x+y=-1
<span>x-3y=11
</span>
x+y = -1-y
-y
x = -1-y
Now apply the value of x into the other equation.
x-3y=11
-1-y-3y = 11
Combine like terms
-4y -1 = 11
+1 +1
-4y = 12
-4y = 12
-4y/-4 = 12/-4
y = -3
Now, apply the value of Y to one equation to find x.
y = -3
x -3 = -1
+3 +3
x= 2
Now we have the value for both, x and y.
x = 2
y =-3
Final answer: A. <span>(2, −3)</span>
Answer:
2 right and 5 down
Step-by-step explanation:
