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3 years ago

SOS!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

alisha [4.7K]3 years ago

5 0

Your answer is option 3. Dashed lines because the inequality on either line is NOT an "or equal to" statement.

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An object is translated by (x - 2; y- 6). If one point in the pre-image has the coordinates (-3, 7), what would be the

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(-5,1) would be the coordinates of its image

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3 years ago

In 1968, it cost $54,000 for a 30 second commercial during the super bowl. In 1973, the cost for a 30 second commercial was $88,

sukhopar [10]

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3 years ago

Create a function that has two distinct roots: - 3/4 and -1?

asambeis [7]

Step-by-step explanation:

Sorry I cant get any more answers but I really hope that this helps

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2 years ago

Read 2 more answers

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago

14] two drivers, starting at the same place, begin driving in opposite directions at the same time. one heads east at 65 kilomet

Juliette [100K]

They are driving in opposite directions, so the velocities need to be added together.
65+85=150
375/150=2.5 hours, or 150 mins
☺☺☺☺

5 0

3 years ago