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garri49 [273]
3 years ago
8

Can somebody give me a Quick answer. First person gets Brainliest.

Mathematics
2 answers:
Evgen [1.6K]3 years ago
4 0

Answer:D

Step-by-step explanation:

Doss [256]3 years ago
3 0

Answer:

D. -4½

Step-by-step explanation:

Remember PEMDAS:

Parentheses

Exponents

Multiply and Divide (in any order)

Add and Subtract (in any order)

\begin{array}{rl}& \dfrac{3}{4}\left(\dfrac{2}{3} + \dfrac{4}{3} \right ) - 9 \div\dfrac{1}{2} \times\dfrac{1}{3} \\\\\text{Do the addition inside parentheses} &\dfrac{3}{4}\left(\dfrac{6}{3} \right ) - 9 \div\dfrac{1}{2} \times\dfrac{1}{3} \\ \\\text{Simplify the new fraction} &\dfrac{3}{4}(2) - 9 \div\dfrac{1}{2} \times\dfrac{1}{3} \\ \\\text{Multiply} &\dfrac{3}{2} - 9 \div\dfrac{1}{2} \times\dfrac{1}{3} \\\\\end{array}

\begin{array}{rl}\text{Invert the fraction and change divide to multiply} &\dfrac{3}{2} - 9 \times 2 \times\dfrac{1}{3} \\\\\text{Cancel the threes} &\dfrac{3}{2} - 3 \times 2\\\\\text{Multiply} &\dfrac{3}{2} - 6 \\\\\text{Find lowest common denominator } &\dfrac{3}{2} - \dfrac{12}{2} \\\\\text{Add the numerators} &\dfrac{-9}{2} \\\\\text{Convert to a mixed number} &=\mathbf{-4\frac{1}{2}} \\\\\end{array}

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A rectangular lot that measures 150 ft by 200 ft is completely fenced. What is the approximate length, in feet, of the fence?
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you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.06, 1.31, 1.28, 0.99, 1.48
lidiya [134]

The mean and (sample) standard deviation σ = 0.2098.

<h3>What exactly would the standard deviation indicate?</h3>

The term "standard deviation" (or "") refers to the degree of dispersion of the data from the mean. Data are grouped around the mean when the standard deviation is low, and are more dispersed when the standard deviation is high.

<h3>According to given information:</h3>

The mean is the product of the dataset's total and the sample size. Mathematically.

\bar{x}=\frac{\sum X_i}{N}

The individual periods are Xi.

The sample size is N.

\sum X i = 1.06 + 1.31 + 1.28 + 0.99,+  1.48 + 1.37+  0.98 + 1.31 + 1.59 + 1.55

\sum X i = 12.92

N = 10

While substituting the value we get:

x = 12.96/10

x = 1.292

The samples' average is 1.292.

The standard deviation:

\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{N}}

\sum(x-\bar{x})^2 = (1.48-1.292)^2+(1.37-1.292)^2+(0.98-1.292)^2+(1.31-1.292)^2+(1.59-1.292)^2+(1.55-1.292)^2.

\sum(x-\bar{x})^2 = 0.43996

Putting into the formula we get:

\sigma=\sqrt{\frac{0.43996}{10}}

σ = √(0.043996)

σ = 0.2098

The mean and (sample) standard deviation σ = 0.2098.

To know more about standard deviation visit:

brainly.com/question/18521100

#SPJ4

I understand that the question you are looking for is:

You measure the period of a mass oscillating on a vertical spring ten times as follows:

Period (s): 1.06, 1.31, 1.28, 0.99, 1.48, 1.37, 0.98, 1.31, 1.59, 1.55

Required:

What are the mean and (sample) standard deviation?

a. Mean: 1.228, Standard Deviation: 0.2135

b. Mean: 1.325, Standard Deviation: 0.1674

c. Mean: 1.292. Standard Deviation: 0.2211

d. Mean: 1.228, Standard Deviation: 0.2098

e. Mean: 1.292, Standard Deviation: 0.2135

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Do you want the graph? 

I'm confused...
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Find the of x in each triangle.
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I pretty sure you either add or subtract to get the answer
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Read 2 more answers
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