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saw5 [17]
3 years ago
13

How to simplify 3(x+2)

Mathematics
1 answer:
Rudik [331]3 years ago
3 0
3(x + 2)
3(x) + 3(2)
3x + 6
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Find ALL solutions: <br><br> x^4 + 8x = 0
zvonat [6]

Answer:

x = 0 or x = -2

Step-by-step explanation:

x^4+8x=0

Step 1: Factor left side of equation.

x(x+2)(x2−2x+4)=0

Step 2: Set factors equal to 0.

x=0 or x+2=0 or x2−2x+4=0

x=0 or x=−2

7 0
3 years ago
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What property is 2*(3*4)=(2*3)*4
Pepsi [2]

Answer:

Step-by-step explanation:

Associative property

6 0
4 years ago
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The total weight of a truck and its load is w pounds. Let /be the weight of the load . When it's empty the truck weighs 2,439 po
emmainna [20.7K]

Answer:

equation will be 2439+/=w

Step-by-step explanation:

It is pretty clear from the question, that

the weight of the load is /. and the weight of the empty truck is 2439 pounds.

It means when we load the truck with '/' pounds load, trucks weight increases and is given by

w = 2439 + /

For Example:

Suppose if load / = 1000 pounds it means weight of the truck after adding the load will be

w=2439+1000=3439 pounds.

6 0
3 years ago
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Help pls my brain be broken​
Dmitry_Shevchenko [17]

Answer:

if it says n- -10 then its 10

if it says n-10 then its 30

Step-by-step explanation:

i dont know if that line is a negative

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3 years ago
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(1 point) A, P and D are n×n matrices. Check the true statements below: A. A is diagonalizable if and only if A has n eigenvalue
yarga [219]

Answer:

Following are the answers to this questions:

A) False.

B) False.

C) True.

D) True.

Step-by-step explanation:

In option A,

Let A is 3 \times 3 diagonal matrices that is,

\left[\begin{array}{ccc}0&1&0\\0&0&6\\0&0&0\end{array}\right]

here A^3= 0, In this A is the nilpotent matrix and A has three values that are equal to 0 but it is not a diagonalizable matrix.

In option B,

If A =\left[\begin{array}{ccc}0&1\\0&0\end{array}\right] in given value A elements are 0 and 1 as a distinct eigen value, that's why A is diagonalizable  but |A| =0 its means A is not invertible, that's why it is false.

In option C,

It is given that A= PDP^{-1} where A~ D, which is A is similar to diagonal matrices, that's why it is true.

In option D,

It is given that A has eigen vector, which leases from R^n. A has eigen vector and A is n \times n matrix, the number of A eigen values = given vector of A, that's why it is correct.  

8 0
3 years ago
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