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Artist 52 [7]
3 years ago
11

I don't understand how to do this can someone help me with this problem? My mid-term is tomorrow and I want one less problem to

get wrong. Thank you !​

Mathematics
1 answer:
Rama09 [41]3 years ago
6 0
∆ on the Left;

x + 95 + 35 = 180°

x + 130 = 180°
x = 50°

In the middle:

50° + 63° + x= 180°

113° + x = 180°

x = 67°

∆ on the right:

67° + 85° + x = 180°

152 + x = 180°
x = 28°
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a right triangle is removed from a rectangle to create the shaded region shown below. find the area of the shaded region. be sur
ser-zykov [4K]

Answer:

36

Step-by-step explanation:

Objective: Find missing dimensions of the right triangle using the then subtract that area of the triangle from the rectangle's area.

Using the definition of a rectangle, the left vertical side measure is 7 and right vertical side is 6. So the missing legs of the triangle is 4 and 3.

Apply triangle formula, base x height divided by 2.

\frac{4 \times 3}{2}  = 6

Area of rectangle is length x width so the area is

7 \times 6 = 42

Subtract 6 from 42.

42 - 6 = 36

3 0
3 years ago
2a + 6 = 6<br> 2a =<br> Subtract 6 from both sides<br> Divide both sides by 2
Alla [95]

Answer:

0

Step-by-step explanation:

2a+6=6

-6=-6

2a=0

2 2

a=0

8 0
3 years ago
Find the missing angle
AnnyKZ [126]

Answer:

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Step-by-step explanation:

7 0
2 years ago
Which of the following statements is NOT true?
yanalaym [24]

Answer:

the second one

Step-by-step explanation:

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5 0
3 years ago
EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of
saw5 [17]

Answer: (a) 0.006

               (b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

                                                       = P(AA) x P(D/AA)

                                                       = 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

                         = P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

                         = 0.3(0.02) + 0.70(0.03)

                         = 0.027

3 0
3 years ago
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