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3 years ago

A car travels at an average speed of 56 miles per hour . how many miles does it travel in 4 hours and 15 minutes

Mathematics

1 answer:

Natali [406]3 years ago

4 0

56 miles per hour

15 minutes is 1/4 of an hour

1/4 = 0.25

so 56 x 4.25 = 238 miles

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Multiply (9-4i)(2+5i)

Tanzania [10]

(9 - 4i)(2 + 5i)

To solve this question you must FOIL (First, Outside, Inside, Last) like so

First:

(9 - 4i)(2 + 5i)

9 * 2

Outside:

(9 - 4i)(2 + 5i)

9 * 5i

45i

Inside:

(9 - 4i)(2 + 5i)

-4i * 2

-8i

Last:

(9 - 4i)(2 + 5i)

-4i * 5i

-20i²

Now combine all the products of the FOIL together like so...

18 + 45i - 8i - 20i²

***Note that i² = -1; In this case that means -20i² = 20

18 + 45i - 8i + 20

Combine like terms:

38 - 37i

^^^This is your answer

Hope this helped!

~Just a girl in love with Shawn Mendes

8 0

4 years ago

Part A: Use the grid to determine in which quadrants the starting point and the finishing point are located. Explain how you det

Ugo [173]

Answer: the answer is in the step by step thing

Step-by-step explanation:

it stars at one, but the original is (0,0) in the graph. But if moves up or so the side 2 times each time.

8 0

3 years ago

Whats the Number of Units and Distance of feet to Mammoth to tempest??

nexus9112 [7]

16 units is the number of units but i’m not sure of distance because it doesn’t say how many units equals a feet.

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2 years ago

A kaleidoscope has been created by cutting a regular hexagonal hole with side length 2 cm through a cylinder. Find the volume of

posledela

Answer:

The volume of the kaleidoscope (hollow cylinder) is 613.33 in.³

Step-by-step explanation:

Here we have;

The equation for the volume of a cylinder given as follows;

Volume of cylinder = π × r² × h

Given that the height, h of the cylinder = 9 cm

The radius, r = 5 cm

Volume of the solid cylinder before cutting out the hexagon hole is thus found as follows;

Volume of cylinder = π × 5² × 9 = 706.86 cm³

Volume of hexagon hole = Area of base × height

Where:

Area, A of a regular hexagon of side a = $\frac{3\sqrt{3} }{2} \times a^2$

Therefore, volume of the regular hexagon = $\frac{3\sqrt{3} }{2} \times 2^2 \times 9 = 93.53 \ in.^3$

Therefore, the volume of the kaleidoscope (hollow cylinder) = 706.86 - 93.53 = 613.33 in.³.

3 0

3 years ago

Word form of 823,774

Rzqust [24]

Eight thousand twenty-three, seven hundred seventy-four

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3 years ago