Line segment JM has endpoints with coordinates 0 and 25 on a number line. Points K and L are on segment JM. K has a coordinate o
f 5 and point L has a coordinate of 12. Find the probability that a point on JM is placed first on JL and a second point is not placed on KL.
1 answer:
You might be interested in
Answer:
So the answer for this case would be n=67 rounded up
Step-by-step explanation:
Information given
represent the sample mean for the sample
population mean
represent the sample standard deviation
n represent the sample size
Solution to the problem
The margin of error is given by this formula:
(a)
And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be , replacing into formula (b) we got:
So the answer for this case would be n=67 rounded up
Step-by-step explanation:
1) i will asume x2 and z2 are squares here.
ok, here we only have restrictions to x and z, so y can take all the values in R.
is a circle of radius 6, you can see this if for example we set z = 0, then x goes from -6 to 6, the same if we set x = 0 then z goes from -6 to 6.
and the equation describes a circle.
So here, the region is the solid cylinder of radius 6, where the Y axis is also the axis of the cylinder.
2) you tipped the same inequality but different numbers in the right side, here i think you are saying that the inequalities describes the set of all points whose distance from the y-axis is equal or less tan 6.