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Over [174]
2 years ago
10

Line segment JM has endpoints with coordinates 0 and 25 on a number line. Points K and L are on segment JM. K has a coordinate o

f 5 and point L has a coordinate of 12. Find the probability that a point on JM is placed first on JL and a second point is not placed on KL.

Mathematics
1 answer:
Pepsi [2]2 years ago
5 0

Answer:

  • D. 216/625

Step-by-step explanation:

  • The length of the segment JM is 25 units.
  • The segment JL is between 0 and 12, so is 12 units.
  • The segment KL is between 5 and 12, so is 7 units.

<u>The probabilities for each point:</u>

  • P(point on JL) = 12/25
  • P(point not on KL) = 1 -  7/25 = 18/25

<u>Required probability:</u>

  • P = 12/25*18/25 = 216/625

Correct choice is D

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Follow the directions to solve the system of equations by elimination. 8x + 7y=39 4x – 14y = -68​
harina [27]

Step-by-step explanation:

Hey there!

Here;

The equations are;

8x + 7y = 39.......(i)

4x - 14y =  - 68..........(ii)

Multiplying equation (i) by 2.

16x + 14y = 78

<u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>1</u><u>4</u><u>y</u><u> </u><u> </u><u> </u><u>=</u><u> </u><u>-68</u>

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x = 1/2.

Putting value of 'x' in equation (i).

8 \times  \frac{1}{2}  + 7y =  39

4 + 7y = 39

7y = 3 9 - 4

y =  \frac{35}{7}

Therefore the value of y is 5.

<u>Check</u><u>:</u>

<u>Put</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>and</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>(</u><u>i</u><u>)</u><u>.</u>

8x + 7y = 39

8 \times  \frac{1}{2}  + 7 \times 5 = 39

4 + 35 = 39

39 = 39

(True).

<u>Therefore</u><u>, </u><u>the</u><u> </u><u>solution</u><u> </u><u>is</u><u> </u><u>;</u><u> </u><u>(</u><u>1</u><u>/</u><u>2</u><u>,</u><u>5</u><u>)</u><u>.</u>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Step-by-step explanation:

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Alja [10]

Answer:

Step-by-step explanation:

One - third = 1/3

then:

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process:

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Check:

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