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kow [346]
3 years ago
15

Assume the random variable x is normally distributed with mean u = 90 and standard deviation o=5. Find the indicated probability

.
P(X<80) =
(Round to four decimal places as needed.)
Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

<u>Given</u>:

Let the random variable x is normally distributed with mean \mu=90 and \sigma=5

We need to determine the probability of P(X

<u>Probability of </u>P(X<u>:</u>

The formula to determine the value of P(X is given by

Z=\frac{X-\mu}{\sigma}

Thus, we have;

P(X

Simplifying, we get;

P(X

P(X

Using the normal distribution table, the value of -2 is given by 0.0228

P(X

Thus, the value of P(X is 0.0228

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Answer:

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Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3
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Please check the explanation.

Step-by-step explanation:

Given the function

f\left(x\right)=\sqrt{x^3-16x}

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

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Thus, identifying the intervals:

-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4

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The domain of the function f(x) is:

x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}

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A dilation is a transformation whose preimage and image are
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