Question

In rectangle PQRS, PQ = 18, PS = 14, and PR = 22.8. Diagonals PR and QS intersect at point T. What is the length of TQ ?

Answer 1

rectangle PQRS, PQ = 18, PS = 14, and PR = 22.8
so
Diagonals PR = QS
if PR = 22.8 then QS = 22.8

TQ = QS/2 = 22.8 / 2 = 11.4

anser
TQ = 11.4

Answer 2

Answer:

TQ =  11.4

Step-by-step explanation:

Given : In rectangle PQRS, PQ = 18, PS = 14, and PR = 22.8. Diagonals PR and QS intersect at point T.

To find : What is the length of TQ .

Solution : We have given rectangle PQRS

Side PQ = 18.

Side PS = 14.

Diagonal  PR = 22.8 .

Properties of rectangle : (1)  Opposite sides of rectangle are equals.

(2) Diagonals of rectangle are equal .

(3)  Diagonals of rectangle bisect each other.

Then by second property :

Diagonal PR= QS .

QS = 22.8

By the Third property  TQ = $\frac{1}{2} * QS$.

TQ =  $\frac{1}{2} * 22.8$.

TQ =  11.4

Therefore, TQ =  11.4