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Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
The height of the tower is 25.5 :))))
Well I am going to assume you need slope-intercept form. So the equation is y=mx+b. m is slope, b is y intercept. So you just plug it in -6= -1/2(6)+b. -6=-3+b. Now you figure out for b so what does b have to be to make the equation equal. Well -3 so -6=-3+-3, or -6=-6.
y=-1/2x-3
Hope that helped
Answer:
2x4y=2... hope this helps.
The answer is D
You just need to subtract term 1 (5) from term 2 (10) to find the answer, and the common difference between each sequential term is 5