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Arlecino [84]
2 years ago
11

Fred walked 20 miles in 8 days. If he continues walking at this rate, how many miles will he walk in 4 weeks? Be sure to set up

a proportion to help you solve.
Mathematics
1 answer:
mamaluj [8]2 years ago
8 0

Answer:

70

Step-by-step explanation:

First, to find the constant rate divided 20 miles by 8 days.

20 ÷ 8 = 2.5

Then, we know that in one week there are seven days so we multiply 2.5 x 7

2.5 x 7 = 17.5

Lastly, multiply 17.5 times 4

17.5 x 4 = 70

MARK BRAINLIEST IF IM RIGHT PLEASE HAPPY TO HELP. HAPPY EARLY THANKSGIVING!!!!!

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Jordan Michael runs a basketball camp. A group of randomly selected camp participants were asked to give their shirt size. The t
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Read 2 more answers
Write an inequality for x that would give this rectangle a perimeter of at least 300ft
Travka [436]

Answer:

The inequality for x is:

x\geq 142

Step-by-step explanation:

Given:

Width of rectangle = 3 ft

Height or length of rectangle = (x+5) ft

Perimeter is at least 300 ft

To write an inequality for x.

Solution:

Perimeter of a rectangle is given as:

⇒ 2l+2w

where l represents length of the rectangle and w represents the width of the rectangle.

Plugging in the given values in the formula, the perimeter can be given as:

⇒ 2(x+5)+2(3)

Using distribution:

⇒ 2x+10+6

Simplifying.

⇒ 2x+16

The perimeter is at lest 300 ft. So, the inequality can be given as:

⇒ 2x+16\geq 300

Solving for x

Subtracting both sides by 16.

⇒ 2x+16-16\geq 300-16

⇒ 2x\geq284

Dividing both sides by 2.

⇒ \frac{2x}{2}\geq \frac{284}{2}

⇒ x\geq 142   (Answer)

7 0
3 years ago
A clothing shop ordered 240 t-shirts. 20% of the shirts are Smalls. How
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Answer:

The answer is 48 small shirts ordered

Step-by-step explanation:

4 0
3 years ago
Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible
djverab [1.8K]

\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}

\text{greater than their HCF.}\\
\\
\text{but here we can see that }LCM

Hence there is no such natural numbers exist.

7 0
3 years ago
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