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brilliants [131]
3 years ago
10

Help me help me help me help me pls

Mathematics
2 answers:
Mandarinka [93]3 years ago
8 0
Answer
The answer is B
ivolga24 [154]3 years ago
7 0

Answer:

b

Step-by-step explanation:

y = -4/3x + 4

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Answer: w hcel eblk lne nleem

Step-by-step explanation:

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4 years ago
What is the slope of a line that goes through the following 2 points<br> (-20-4) (-12,-10)<br> 1
wolverine [178]
-6/8

The slope formula is m=(y2-y1)/(x2-x1)
5 0
3 years ago
Can somebody help teach me how to solve quadratic equations? I have no idea what to plug in. Here are some examples of what I ne
guapka [62]
The best method that will work for any quadratic equation is to use the quadratic formula: x = (-b±√(b² - 4ac))/2a, this will work for any quadratic of the form ax² + bx + c = 0.

As for the last equation in the attachment, that is a cubic equation, these are much trickier to solve and as such the formula is much longer and very complicated. Therefore it is easier to see if it can be broken down into a linear term and a quadratic. This can be done by substituting integer values of x into the equation to see if it holds true. If both sides of the equation are equal for a given value of x then the equation ax³ + bx² + cx + d can be rewritten as (Ax + B)(px² + qx + r). This can then be put into the quadratic formula mentioned above.
4 0
3 years ago
I WILL GIVE BRAINLIEST!
Illusion [34]

Answer:

24 ft cubed

Step-by-step explanation:

The volume of a rectangular prism is denoted by the formula: V=lwh , where l is the length, w is the width, and h is the height.

Looking at the diagram, we can see that the length is 2 ft (so l = 2), the width is 4 ft (so w = 4), and the height is 3 ft (so h = 3). Now, we can just plug in these values to find V, the volume:

V=lwh

V=2*4*3=24

Thus, the answer is 24 ft cubed.

Hope this helps!

7 0
4 years ago
Read 2 more answers
What are solutions to the equation sinx cosx = square root 3 over4
andrey2020 [161]
\sin(x)\cos(x)=\dfrac{\sqrt{3}}{4}\\\\2\sin(x)\cos(x)=\dfrac{\sqrt{3}}{2}\\\\\sin(2x)=\dfrac{\sqrt{3}}{2}\\\\2x=\arcsin\left( \dfrac{\sqrt{3}}{2} \right)\\\\2x=\left\{ \dfrac{\pi}{3},\dfrac{2\pi}{3}\right\}+2n\pi\\\\\boxed{x=\left\{ \dfrac{\pi}{6},\dfrac{\pi}{3}\right\}+n\pi}

7 0
4 years ago
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