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shtirl [24]
3 years ago
8

I have no clue what this is pls help me!!!!

Mathematics
1 answer:
zaharov [31]3 years ago
3 0

Answer:

Label theta as the missing length. You are solving circle segment so use the formula

Area of Segment =  θ − sin(θ)2 × r2   (when θ is in radians)

Area of Segment = (  θ × π360 −  sin(θ)2  ) × r2   (when θ is in degrees)

So the answer would be 7.68

Step-by-step explanation:

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Solve for X. First to answer is marked branliest.
Bas_tet [7]

Answer:

Step-by-step explanation:

Solution

Here,

h²=p²+b²

or,15²=x²+7²

or,225=x²+49

or,x²=225-49

or,x²=176

x=13.266

If you found my answer useful then please mark me brainliest.

8 0
3 years ago
A recent study reported that high school students spend an average of 94 minutes per day texting. Jenna claims that the average
larisa [96]

Answer:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

Step-by-step explanation:

Jenna claims that the average time of texting at her larger high school is greater than 94 minutes per day.

From here we can see that we have to perform a hypothesis test about a sample mean. The null and alternate hypothesis will be:

Null Hypothesis: \mu \leq  94

Alternate Hypothesis: \mu > 94

Jenna collected data from a sample of 32 students. So, sample size will be:

Sample Size = n = 32

Sample Mean = x = 96.5

Sample Standard Deviation = s = 6.3

We have to perform a hypothesis test, to test Jenna's claim. Since, the value of Population Standard Deviation is unknown and the value of Sample Standard Deviation is known, we will use One Sample t-test in this case.

The formula to calculate the test statistic is:

t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}

Using the values, we get:

t=\frac{96.5-94}{\frac{6.3}{\sqrt{32} } }=2.245

The degrees of freedom will be:

df = n - 1 = 32 - 1 = 31

We have to convert the t-score 2.245 with 31 degrees of freedom to its equivalent p-value. From t-table this value comes out to be:

p-value = 0.0160

The significance level is:

\alpha =0.05

Since, the p-value is lesser than the level of significance, we reject the Null Hypothesis.

Conclusion:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

3 0
4 years ago
May someone help me / giving crown / giving 15 points
Triss [41]

Answer: 3 and 192

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
The table shows the change in the depth of the water during each 2-hour period until 8:00pm. The depth of water was 4.3 feet at
Whitepunk [10]

Answer:

6.4 ft

Step-by-step explanation:

7 0
3 years ago
How do you write 6.8 as a percentage?
kap26 [50]
6.8 is 680/100 or 680%

6.8 = 680%
4 0
3 years ago
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