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MrRa [10]
3 years ago
14

Two students are working together on an experiment that measures the effect of different liquid fertilizers on the thickness of

plants’ stems. Which is most likely to result in the greatest amount of error in their scientific experiment?
One student measures the plant stem widths by using calipers. The other student measures the widths of the same plant stems again by using a different pair of calipers.

One student measures the plant stem widths by using calipers. The other student types the measurements as they are taken into a computer spreadsheet.

One student measures liquids for the experiment by holding the flask up at eye level. The other student measures liquids for the experiment while the flask sits on the table.

One student weighs liquids for the experiment by using a calibrated scale. The other student weighs liquids for the experiment by using a different calibrated scale.
Physics
2 answers:
prohojiy [21]3 years ago
8 0
I would say the greatest amount of error is introduced by eyeballing the flask at two different levels. You're supposed to measure liquids at eye level. The angle viewing downward could be off by a good amount
SOVA2 [1]3 years ago
4 0
I'm pretty sure the answer is C.
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A 325-g model boat facing east floats on a pond. The wind in its sail provides a force of 1.85 N that points 25° north of east.
podryga [215]

Answer:

Vf = 4.40  m/s  and  θ = 88º

Explanation:

To solve this problem, let's look for the resultants of the force and with this we calculate the accelerations in each axis.

Let's use trigonometry to break down the forces

     Sin 25 = F1x / F1

     Cos 25 = F1y / F1

     Fix = F1 sin 25

     F1x = 1.85 sin 25

     F1x = 0.78 N

     F1y = 1.85 cos 25

     F1y = 1.67 N

     F2 = - 0.782 N j ^  (south)

     F3 = - 0.750 N i ^    (west)

We write Newton's second law

X axis (East-West)

     F1x - F3 = m ax

     ax = (F1x - F3) / m

     ax = (0.78 - (0.750)) / 0.325

     ax = 0.092 m / s²

Y axis (North-South)

     F1y - F2 = m ay

     ay = (1.67- (0.782)) / 0.325

     ay = 2.73 m / s²

Let's calculate the magnitude and direction of the acceleration

     a = RA ax2 + ay2

     a = RA 0.092² + 2.73²

     a =  2.73m / s²

     tan θ = ay / ax

     θ = tan⁻¹ (2.73/0.092)

     θ = tan⁻¹ 29.67

     θ = 88º

We calculate the speed, notice that we use the total acceleration to be able to use the totol displacement

Vf² = vo² + 2 at D

Vf² = 0 + 2 2.73 3.55

Vf = √ 19.38

Vf = 4.40  m / s

θ = 88º

8 0
3 years ago
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