Question

Suppose you increase your walking speed from 6 m/s to 14 m/s in a period of 1 s. What is your acceleration?

Answer 1

A = delta v over delta t delta v is calculated with final velocity less initial velocity so delta v is 14 - 6 that is 8m/s and delta t is calculated with final time less initial time as initial always is 0 then is 1 - 0 that is 1 then a = 8m/s over 1 that is 8 then the acceleration is 8m/s^2 (remember that is squared.)

Answer 2

Answer:
acceleration = 8 m/s²

Explanation:
Acceleration is defined as the rate of change of velocity.
This means that:
acceleration = $\frac{v2 - v1}{t2 - t1}$
We are given that:
V2 = 14 m/sec
V1 = 6 m/sec
We are also given that the duration is 1 sec, this means that:
t2 = 1 sec
t1 = 0 sec

Substitute with the givens in the above equation to get the acceleration as follows:
acceleration = $\frac{14-6}{1-0}$ = $\frac{8}{1}$ = 8 m/s²

Hope this helps :)