We have that the see-saw will be balance if a weight of
is added to Nural's side of the see-saw

From the Question we are told that
Wan’s mass is 
Nurul’s mass is 
Generally
The Will be balance when the weight on both sides of the see-saw are equal




In conclusion
The see-saw will be balance if a weight of
is added to Nural's side of the see-saw

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Answer:
Magnetic dipole moment is 0.0683 J/T.
Explanation:
It is given that,
Length of the rod, l = 7.3 cm = 0.073 m
Diameter of the cylinder, d = 1.5 cm = 0.015 m
Magnetization, 
The dipole moment per unit volume is called the magnetization of a magnet. Mathematically, it is given by :


Where
r is the radius of rod, r = 0.0075 m


So, its magnetic dipole moment is 0.0683 J/T. Hence, this is the required solution.
Answer:
<em>A. 751 ohm</em>
Explanation:
Impedance: <em>This is the total opposition to the flow of current in an a.c circuit by any or all of the three circuit elements ( R, L, C). The unit of impedance is Ohms (Ω). The impedance in a parallel circuit is gives a s</em>
<em>Z = RXₐ/√(Xₐ² + R²)............................... Equation 1</em>
<em>Where Z = The impedance of the a.c circuit, Xₐ = capacitive reactance, R = resistance.</em>
<em>Given: Xₐ = 962 Ω, R = 1200 Ω</em>
<em>Substituting these values into equation 1,</em>
<em>Z = 962×1200/√(962² + 1200²)</em>
<em>Z = 1154400/√(925444 + 1440000)</em>
<em>Z = 1154400/√(925444+1440000</em>
<em>Z = 1154400/1538</em>
<em>Z = 750.59 Ω</em>
<em>Z≈ 751 Ω</em>
<em>Therefore the impedance of the circuit = 751 Ω</em>
<em>The right option is A. 751 ohm</em>