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Anarel [89]
3 years ago
14

It was recently estimated that homes without children outnumber homes with children by about seven to five. If there are 2556 ho

mes in a county, how many of them are homes without children?
Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

929  

Step-by-step explanation:

For every 11 children, 7 will have homes and 4 will not.

The fraction of children without homes is 4/11.

The number of children without homes is

4/11 × 2556 = 929

 

Check:

The number of children with homes is 2556 - 929 = 1627

With/Without = 1627/929 = 7.005/4 ≈ 7/4

OK.

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See,u have y+5x=6                                                                    ( * =multiplication sign)
and x=-1,0,1
so ,u have to do is substitute x with numbers u have
so,for -1,u have y+5*-1=6
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=y=6-0=6

(3)y +5*1=6
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