It was recently estimated that homes without children outnumber homes with children by about seven to five. If there are 2556 ho
mes in a county, how many of them are homes without children?
1 answer:
Answer:
929
Step-by-step explanation:
For every 11 children, 7 will have homes and 4 will not.
The fraction of children without homes is 4/11.
The number of children without homes is
4/11 × 2556 = 929
Check:
The number of children with homes is 2556 - 929 = 1627
With/Without = 1627/929 = 7.005/4 ≈ 7/4
OK.
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