2 3/4 divided by 1/4
is
2 3/4 multiplied by 4/1
which is (2+3/4)*4 = 2*4 + 3/4*4 = 8+3 =<em>11</em>
Answer:
a) x1 = 6 and x2 = -2
b) -2
Step-by-step explanation:
a)
To find the roots of the quadratic equation, we can use the Bhaskara's formula:
Delta = b^2 - 4ac
Delta = (-4)^2 - 4*1*(-12) = 64
sqrt(Delta) = 8
x1 = (-b + sqrt(Delta)) / 2a
x1 = (4 + 8) / 2
x1 = 6
x2 = (-b - sqrt(Delta)) / 2a
x2 = (4 - 8) / 2
x2 = -2
b)
The roots are 6 and -2, so the smaller root is -2
Answer:
4m^2np^2√3n
Step-by-step explanation:
Answer: lmk
Step-by-step explanation:
Answer: The correct option is
(D) {3, 10, 17, 24, …}.
Reasoning:
We are given to select the sequence that represents the following function with a domain of natural numbers :
The set of natural numbers is {1, 2, 3, 4, . . .}
to find the sequence, we need to substitute x = 1, 2, 3, 4, . . . in equation (i).
From equation (i), we get
Therefore, the sequence that represents the given function is {3, 10, 17, 24, …}.
Thus, option (D) is CORRECT.
