1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
crimeas [40]
3 years ago
14

Using the right triangle Find the value of x' 13 X 12

Mathematics
1 answer:
sineoko [7]3 years ago
4 0

Answer:

5

Step-by-step explanation:

Apply Pythagorean theorem

13 {}^{2}  = 12 {}^{2}  + x {}^{2}  \\ 169 = 144 + x {}^{2}  \\ x {}^{2}  = 169 - 144 \\ x {}^{2}  = 25 \\ x =  \sqrt{25}  \\ x = 5

You might be interested in
Help please with this​
PolarNik [594]

Answer:

C. 54

Step-by-step explanation:

I just answered the expression as i went and I got 54.

4 0
3 years ago
Read 2 more answers
In the xy-plane, the midpoint M of segment AB has coordinates (-1,3), and point A has coordinates
Marina CMI [18]
I think it’s 3 because if u do a -3 and a positive 0 the answer would be 3
7 0
3 years ago
catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts. A banquet committee is to select 7 ​appetizers, 8 main​
guapka [62]

Answer:  The required number of ways is 46200.

Step-by-step explanation:  Given that a catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts.

A banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts.

We are to find the number of ways in which this can be done.

We know that

From n different things, we can choose r things at a time in ^nC_r ways.

So,

the number of ways in which 7 appetizers can be chosen from 8 appetizers is

n_1=^8C_7=\dfrac{8!}{7!(8-7)!}=\dfrac{8\times7!}{7!\times1}=8,

the number of ways in which 8 main courses can be chosen from 11 main courses is

n_2=^{11}C_8=\dfrac{11!}{8!(11-8)!}=\dfrac{11\times10\times9\times8!}{8!\times3\times2\times1}=165

and the number of ways in which 4 desserts can be chosen from 7 desserts is

n_3=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.

Therefore, the number of ways in which the banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts is given by

n=n_1\times n_2\times n_3=8\times165\times35=46200.

Thus, the required number of ways is 46200.

7 0
4 years ago
Question 1 (Essay Worth 10 points)
mars1129 [50]

Part A: Garcia mixed 4 cups of red with 1 cup of yellow.

Part B: 1/4 because 4 cups of red requires 1 cup of yellow, so 1 divided by 4 is 1/4.

Part C: $7

Hope this helps! :)

3 0
3 years ago
Read 2 more answers
HELP ME PLEASE ILL GIVE BRAINLIST
bonufazy [111]

Answer:

I would say that the last one is False and A and C are true.

Hope this works.

6 0
3 years ago
Other questions:
  • What is the degree measure of x in this triangle?
    5·2 answers
  • a carpenter needs 30 rafters, each 380cm long. find the total length of rafters in meters. (2 steps)
    5·1 answer
  • What is the slope of a line that passes through each pair of points (2,2), (3,1)
    14·1 answer
  • Show the work of 84 divide by 4
    10·1 answer
  • A business has $15,000 to spend on airline tickets to travel to a conference. It wants 27 of its employees to attend. The busine
    8·1 answer
  • Can you please help me ​
    13·1 answer
  • Printer A prints 36 pages every 1.5 minutes. Printer B prints 114 pages every 3 minutes.
    9·2 answers
  • Somebody help with bothhh
    8·1 answer
  • In which quadrant does θ lie given that sinθ < 0 and cosθ < 0? Thank You!
    8·2 answers
  • Angie read 2 books in 5 days, and each book contained 330 pages. If Angie read the same number of pages each day, how many
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!