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artcher [175]
3 years ago
14

Assume m<2 = 35°. Find the measure of all of the other

Mathematics
2 answers:
ra1l [238]3 years ago
8 0

m∠1 = 145 degrees (supplementary angle and corresponding to ∠5)

m∠3 = 35 degrees (vertical, supplementary angle and corresponding to ∠7)

m∠4 = 145 degrees (supplementary, verticle angle and corresponding to ∠8)

m∠5 = 145 degrees (supplementary and corresponding to m∠1)

m∠6 = 35 degrees (supplementary and corresponding to m∠2)

m∠7 = 35 degrees (supplementary, corresponding to ∠3, and verticle angle)

m∠8 = 145 degrees (supplementary, corresponding to m∠4 and verticle angle)

they are all supplementary angles bc the lines l and p are parallel.

some other angles 'cause why not.

alternate interior angles: ∠3 & ∠6; ∠4 & ∠5

Alternate exterior angles: ∠2 & ∠7; ∠1 & ∠8

Same side interior: ∠3 & ∠5; ∠4 & ∠6

Same side exterior: ∠1 & ∠7; ∠2 & ∠8

soldi70 [24.7K]3 years ago
6 0

  1. m<1 = 145 | Supplementary
  2. m<3 = 35 | Vertical
  3. m<4 = 145 | Supplementary
  4. m<5 = 145 | (With Angle 4) If parallel then alternate interior angles congruent
  5. m<6 = 35 | (With Angle 5) Supplementary
  6. m<7 = 35 | (With Angle 6) Vertical
  7. m<8 = 145 | (With Angle 7) Supplementary

Hope it helps <3

(If it does, maybe brainliest :) Need one more for rank up)

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7 0
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Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of
alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

- The standard form of the linear equation is Ax + BC = C, where

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- The median of a trapezoid is a segment that joins the midpoints of

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# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

 parallel bases and which of them are the non-parallel bases

# The side RS

∵ m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}

# The side ST

∵ m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}

# The side TU

∵ m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}

# The side UR

∵ m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

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∵ The median of a trapezoid is a segment that joins the midpoints of

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∵ The midpoint of RS = (\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

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∵ The mid point of Rs is (0 , 13/2)

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- Multiply the two sides by 6 to cancel the denominator

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- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

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Marrrta [24]

Alright, lets get started.

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So, the equation is x + 2 y = 18 :   Answer

Hope it will help :)




8 0
3 years ago
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