Answer:
Triangle APB is an isosceles triangle ⇒ 3rd answer
Step-by-step explanation:
* Lets explain the how to solve the problem
- ABCD is a square
∴ AB = BC = CD = AD
∴ m∠A = m∠∠B = m∠C = m∠D = 90°
- DPC is equilateral triangle
∴ DP = PC = DC
∴ m∠DPC = m∠PCD = m∠CDP = 60°
- In the Δs APD , BPC
∵ AD = BC ⇒ sides of the square
∵ PD = PC ⇒ sides of equilateral triangle
∵ m∠ADB = m∠BCP = 30° (90° - 60° = 30) ⇒ including angles
∴ Δs APD , BPC are congregant ⇒ SAS
- From congruent
∴ AP = BP
∴ Triangle APB is an isosceles triangle
Explanation is in the file
tinyurl.com/wpazsebu
Sin = Opposite/ Hypotenuse
Sin (theta)= 5/10
Sin^-1(5/10)=30
theta=30
Answer:
324
Step-by-step explanation:
4x3=12
12x3=36
36x3=108
108x=324
Answer:
x=6 y=-3
Step-by-step explanation:
