Answer: 12πins.
Step-by-step explanation:
Since the area if a circle = πr²
From the question
Area of the circle = 36πins²
To find the circumference of the circle, we need to find the common radius of the circle and this could be achieved from the area of the circle given above.
πr² = 36π, solving this gives. Divide through by π
r² = 36
r = +/-√36
= +/-6
Now to find the circumference of the circle, we substitute for r in the formula below.
Circumstances = 2πr
= 2 ×π × 6
= 12πins.
<h2>
Answer:</h2><h2>
The probability that Roy gives randomly an SUV = 15 / 47</h2>
Step-by-step explanation:
The total number of used cars owned by Roy = 47
[12 trucks + 20 cars + 15 SUV = 47 cars]
The total number in sample space, n (S) = 47
The probability that Roy is giving away and SUV = ?
Let A be the event that Roy is giving an SUV
Total no of SUV's , n (A) = 15
The probability of giving an SUV, P (A) = n (A) / n (S)
P (A) = 15 / 47
Answer:
15%
Step-by-step explanation:
pretty sure thats right
Answer:
The third score must be larger than or equal to 72, and smaller than or equal 87
Step-by-step explanation:
Let's name "x" the third quiz score for which we need to find the values to get the desired average.
Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

This inequality tells us that the score in the third quiz must be larger than or equal to 72.
Now we study the second inequality to find the other restriction on "x":

This ine
quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.
Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87: