Answer: <em>33 square feet</em>
Step-by-step explanation:
<em>First, let's take the area of the rectangle shown here which is 6ft long and 4ft wide</em>
<em>6x4=24</em>
<em>Now let's take the area of the square which is 3ft long and 3ft wide</em>
<em>3x3=9</em>
<em>Now add 24 and 9 for the total area</em>
<em>24+9=</em><em>33 square feet</em>
Answer:

Step-by-step explanation:
We have two coordinate points and are asked to find a slope.
When finding slope, we can use the formula listed :

To understand what the variables are, you can take this :


Substitute the points :


Now substitute it into the formula :



Answer: (x)(x)(x) = x^3.
Step-by-step explanation:
x^3 means multiply x by it's self 3 times.
Hope this helps..
Height of tree is given by the distance multiplied by the tangent of the angle of elevation:
Height = 30*tan(40) = 30(0.8391)=25.17 ft
Answer: 
<u>Step-by-step explanation:</u>
![12cos\bigg(\dfrac{2\pi}{5}x\bigg)+10=16\\\\\\12cos\bigg(\dfrac{2\pi}{5}x\bigg)=6\\\\\\cos\bigg(\dfrac{2\pi}{5}x\bigg)=\dfrac{1}{2}\\\\\\cos^{-1}\bigg[cos\bigg(\dfrac{2\pi}{5}x\bigg)\bigg]=cos^{-1}\bigg(\dfrac{1}{2}\bigg)](https://tex.z-dn.net/?f=12cos%5Cbigg%28%5Cdfrac%7B2%5Cpi%7D%7B5%7Dx%5Cbigg%29%2B10%3D16%5C%5C%5C%5C%5C%5C12cos%5Cbigg%28%5Cdfrac%7B2%5Cpi%7D%7B5%7Dx%5Cbigg%29%3D6%5C%5C%5C%5C%5C%5Ccos%5Cbigg%28%5Cdfrac%7B2%5Cpi%7D%7B5%7Dx%5Cbigg%29%3D%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5C%5Ccos%5E%7B-1%7D%5Cbigg%5Bcos%5Cbigg%28%5Cdfrac%7B2%5Cpi%7D%7B5%7Dx%5Cbigg%29%5Cbigg%5D%3Dcos%5E%7B-1%7D%5Cbigg%28%5Cdfrac%7B1%7D%7B2%7D%5Cbigg%29)
