The best and most correct answer among the choices provided by the first question is letter E which is all of the above.

On the other hand, the best and most correct answer among the choices provided by the second question is letter A which is rebirth and coming death.

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!

7 0

3 years ago

find the Taylor Series for tan−1(x) based at 0. Give your answer using summation notation and give the largest open interval on

enyata [817]

Let $f(x)=\tan^{-1}x$ . Then $f'(x)=\frac1{1+x^2}$ . Note that $f(0)=0$ .

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n$

This means that for $|-x^2|=|x|^2$ , or $-1$ , we have

$\displaystyle f'(x)=\frac1{1+x^2}=\frac1{1-(-x^2)}=\sum_{n\ge0}(-x^2)^n=\sum_{n\ge0}(-1)^nx^{2n}$

Integrate the series to get

$f(x)=f(0)+\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

$\implies\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

6 0

3 years ago

Show me the work to this problem 4 1/8 + 2 3/5

Nonamiya [84]

Answer:

6 29/40

Step-by-step explanation:

1/8 times 5 equals 5/40 and 3/5 times 8 equals 24/40 you add them together to get 29/40 which can not be simplified then add 4 and 2 to get 6 so <u>6 29/40 </u>is your answer.

3 0

3 years ago

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