5(2x+7x)=-31 +36 whats the anser
2 answers:
You might be interested in
Answer: Both in favor and against: 3/6 OR 1/2 OR 50%.
Step-by-step explanation: Both in favor and against: 3/6 OR 1/2 OR 50%.
The probability of rolling one die and getting any digit is . That is because the desired outcome is only 1 digit out of the 6 total digits on each of the six sides.
That means the probability of rolling either a 1, a 2, or a 4 <em>if you are looking for any of those numbers specifically, </em>is . But! You are looking to roll a 1, a 2, or a 4, without any preference among those three. Therefore, you are going to add the desired outcomes.
= 0.5 = 50%
Above, are added the probability of rolling a 1 PLUS the probability of rolling a 2 PLUS the probability of rolling a 4, yielding a 50% probability.
Think about it. There are six total digits on a die. You are okay with rolling three of those. Three is half of six. Therefore, the probability of rolling the number you'd like is one-half, fifty-percent.
Likewise, since the probability of all complement events happening is 1 (or 100%), The odds against rolling either 1, 2, or 4 is also fifty-percent. 100% (which is rolling <em>any </em>number on a die) MINUS 50% (which is rolling a 1, a 2, or a 4 with no preference) EQUALS TO 50% (which is rolling a 3, a 5, or a 6).
Answer:
A
Step-by-step explanation:
The graphs are attached.
First of all, the day proposal goes out, 25 people know, so the initial condition is y = 25 at x = 0.
Hence, graph would start at y = 25.
Looking at the graphs, we can eliminate B and D immediately because they start at 50.
Now, it says every day, this number (y) triples, so 1 day after, it would be:
25 * 3 = 75
So, the graph would show x = 1 and y = 75
We can eliminate "C" as it doesn't show 75 at x = 1.
And we look at A and it is correct.
So,
A is the graph of the situation represented.
// I AM NOT SURE, IF SOMEONE SEES THIS AND ITS WRONG CORRECT ME DIRECTLY.
hmm.. never heard of properties but take a look at this :D
hmm.. never heard of properties but take a look at this :D