Part A:
Given that <span>her score is always in between the lowest score and the highest score shown.
</span>From the figure, Lee's lowest score wss 4 1/2 and her highest score was 5.
From the cards given, the number in the card between 4 1/2 and 5 is 4 3/4.
Part B:
Given that <span>her score is always in between the lowest score and the highest score shown.
</span>From the figure, Lee's lowest score wss 0.325 and her highest score was 0.35.
From the cards given, the number in the card between 0.325 and 0.35 is 0.349.
Part C:
Given that <span>her score is always in between the lowest score and the highest score shown.
</span>From the figure, Lee's lowest score wss 0.35 and her highest score was 0.375.
From the cards given, the number in the card between 0.35 and 0.375 is 0.365.
Part D:
Given that <span>her score is always in between the lowest score and the highest score shown.
</span>From the figure, Lee's lowest score wss 0.2 and her highest score was 0.225.
From the cards given, the number in the card between 0.2 and 0.225 is 0.221.
Part E:
Given that <span>her score is always in between the lowest score and the highest score shown.
</span>From the figure, Lee's lowest score wss 2 3/4 and her highest score was 3.5.
From the cards given, the number in the card between 2 3/4 and 3.5 is 2.751.
Hello there!
Let's put these into simpler terms:
-7s + 3s + 2s
10 - 8 - 7
-7s + 3s = -4s
-4s + 2s = 2s
10 - 8 = 2
2 - 7 = -5
We are now left with:
2s - 5, which is your simplified expression.
I hope this helps!
Answer:
C. in; in; in²
Step-by-step explanation:
Perimeter and height are given in regular units. Area is given in square units.
(8c+2a)(4+b)
(8c)(4)+(8c)(b)+(2a)(4)+(2a)(b)
32c+8bc+8a+2ab
2ab+8bc+8a+32c
2/3 is greater because 3/8 is less than 1/2 while 2/3 is greater than 1/2