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3 years ago

What is an advantage of consuming natural foods instead of dietary supplements?

2 answers:

6 0

Natural foods contain substances that protect the body against diseases, and are often more satisfying than supplements.

ollegr [7]3 years ago

6 0

Answer with explanation:

Dietary supplements don't have all the nutrients you need that a natural food has .

Natural food has beneficial nutrients such as flavonoids and antitoxidants, that aren't in most supplements.

The fresh food is loaded with nutrients that are necessary for good health, such as magnesium,calcium ,and Vitamin A and C etc.

Whereas the dietary supplements in much amount can actually harm us.

for example: Extra Vitamin A supplements can lead to dangerous,toxic levels if taken too frequently.

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Hkdjdnx dndnen be. Dj Dj bc xhdndn b dnxbdjxjd dndjdnc

Serga [27]

Answer:

EASY YOUR MOM.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is 4 to the power of x minus 3 =18

mote1985 [20]

3 to the power of 4:

=34
x
n
=
3
4

=3⋅3⋅3⋅3
=
3
⋅
3
⋅
3
⋅
3

=81
=
81

For example, 3 to the power of -4:

=3−4
x
n
=
3
−
4

=134
=
1
3
4

=13⋅3⋅3⋅3
=
1
3
⋅
3
⋅
3
⋅
3

=181
=
1
81

=0.012346

7 0

2 years ago

If 32^2c= 8^c+7, what is the value of c

Leona [35]

$\bf 32^{2c}=8^{c+7}~~ \begin{cases} 32=2\cdot 2\cdot 2\cdot 2\cdot 2\\ \qquad 2^5\\ 8=2\cdot 2\cdot 2\\ \qquad 2^3 \end{cases}\implies (2^5)^{2c}=(2^3)^{c+7} \\\\\\ 2^{5(2c)}=2^{3(c+7)}\implies \stackrel{\textit{if the bases are the same, then so are the exponents}}{5(2c)=3(c+7)\implies 10c=3c+21} \\\\\\ 7c=21\implies c=\cfrac{21}{7}\implies c=3$

3 0

2 years ago

Read 2 more answers

a group of astronauts launched a model rocket from a platform. Its flight path is modeled by h= -4t^2+24t+13 where h is the heig

Eddi Din [679]

Answer:

6.5 seconds

Step-by-step explanation:

Keep in mind that when $h=0$ , this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

$h=-4t^2+24t+13\\\\0=-4t^2+24t+13\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-24\pm\sqrt{24^2-4(-4)(13)}}{2(-4)}\\ \\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{784}}{-8}\\\\t=\frac{-24\pm28}{-8}\\\\t=\frac{-24-28}{-8}\\ \\t=\frac{-52}{-8}\\ \\t=\frac{52}{8}\\\\t=6.5$

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds

5 0

2 years ago

Read 2 more answers

Given that r is the midpoint of qs and that the lenght of qr is 5.7, find the lenght of qs

ra1l [238]

We know that the midpoint is the a point in the center of the line (r). This means that from the midpoint to the endpoint (qr) is half the length of the overall line. This means that 5.7 (the length of qr) units is half the length of the line. Two halves make a whole so 5.7 × 2 = 11.4 units as the length of the entire line qs.
Hope this helps!

5 0

3 years ago