3 years ago

50 points for the correct answer if u spam u getting reported

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

8 0

The answer is 16, you just have to simply the whole problem

Ghella [55]3 years ago

4 0

16

HhhhIT IS 16 obviously boi

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Can someone hello son please make sure it’s right :)

Sedaia [141]

Answer: x= -12

Step-by-step explanation:

These are corresponding angles which means they are the same. X+62= 50. Subtract 62 from both sides. X= -12

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2 years ago

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Solve the equation.<br><br> −10x + 1 + 7x = 37

matrenka [14]

You combine like terms which are -10x and 7x and 1 and 37. Then it becomes -3x=36. x would equal to 36/-3, which is -12.

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3 years ago

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Ivanshal [37]

Answer:

Step-by-step explanation:

6 0

3 years ago

5(n+1) = 2n + 20 can someone tell me the answer and explain

finlep [7]

Answer:

n=15

Step-by-step explanation:

5(n+1)=2n+20

U start by expanding the first term which will give you 5n+5

Then after that u collect like terms giving u

5n-2n=20-5

Finally u evaluate it giving u

n=15

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3 years ago

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In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo

Scorpion4ik [409]

Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

we have

$A=17\ cm^2$

$AB=(3x-2)\ cm$

$BC=(x+3)\ cm$

substitute the values

$17=\frac{1}{2}(3x-2)(x+3)$

$34=(3x-2)(x+3)$

$34=3x^2+9x-2x-6$

$3x^2+7x-6-34=0$

$3x^2+7x-40=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2+7x-40=0$

$a=3\\b=7\\c=-40$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

$x=\frac{-7(+/-)\sqrt{529}} {6}$

$x=\frac{-7(+/-)23} {6}$

$x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}$

$x=\frac{-7(-)23} {6}=-5$

therefore

The solution is

$x=\frac{8}{3}\ cm$

6 0

2 years ago